Can I override a CUDA host-and-device function with a host-only function?

问题

Consider the following program:

class A {
    __host__  __device__ void foo();
};

class B : A {
    __host__ void foo();
};

int main()
{
    A a; (void) a; 
    B b; (void) b;
}

This compiles (GodBolt) with nvcc 10.

Yet, in more complex programs, I sometimes get the following error (line breaks for readability):

whatever.hpp(88): error: execution space mismatch: overridden entity (function
"C::foo") is a __host__ __device__ function, but overriding entity (function "D::foo")
is a __host__ function

So, nvcc is telling me that I'm not supposed to drop an execution space when overriding methods. I'm not asking about my own code (which I haven't cited here), but about the principle:

• If it's acceptable to override __host__ __device__ functions with just __host__ functions (which I find reasonable) - then how can nvcc even have such an error?
• Alternatively, if it's not allowed - why is the small program above compiling?

回答1:

Overriding (virtual) methods must respect execution space choice of the overridden method.

"overriding" is only relevant to virtual methods - so it must be the case that your C::foo() is marked virtual. And indeed, if we mark foo() in the example program as virtual:

class A {
    virtual __host__  __device__ void foo();
};

class B : A {
    __host__ void foo(); // can say "override" here; but it doesn't matter
};

int main()
{
    A a; (void) a; 
    B b; (void) b;
}

This will fail to compile:

<source>(6): error: member function declared with "override" does not override
a base class member

Does this limitation make sense? One could imagine an interpretation in which the base-class method will apply to __device__-side calls, and the subclass method to __host__-side calls. But that too is a bit awkward - and we need to call something when acting on an object via a base class ptr.

来源：https://stackoverflow.com/questions/59364271/can-i-override-a-cuda-host-and-device-function-with-a-host-only-function