PagedList using LINQ Skip and Take, but show paging using Count of results

南楼画角 提交于 2019-11-27 14:34:15

问题


I am trying to display a filtered list of of products, based on Category filter and ItemsPerPage but I'm having some issues when trying to use it with PagedList.

Someone with PagedList expertise could advice me if I need to write my own pagination code or is there a way to get the results I need using PagedList.

I am using LINQ's Skip & Take functions to get only the number of rows that need to be displayed on the current page, but I would still like paging links to show pages based on the filter's total count.

E.g.: my search filter finds 50 results, but since my rows per page is say 10 items, I use LINQ's Skip() & Take() to get only 10 rows back. I still need to show in my View.cshtml the page links << 1 | 2 | 3 | 4 | 5 >> Right now with default PagedList, I only get << 1 >>, I know why I only see one page but just wanted to know how can I make it work to show correct number of page links, while only getting a subset of results.

**My goal is to write optimized queries to the Database so the web page response performance will be fast.

Here is what my code for the Action Method looks like. The code is getting the correct results but the pagination is not working as I need it to be:

public ViewResult List(int page =1, string category =null)
{
    if (category != null) this.CurrentCategory = category;

    var products = repository.Products
                    .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory)
                    .OrderBy(p => p.ProductID)
                    .Skip((page -1) * PageSize)
                    .Take(PageSize);

    return View(products.ToList().ToPagedList(page, PageSize));
}

Here is the code snippet from the View that deals with pagination. I looked into the project's Github site but could not find an extension method to provide custom pages. I think it will only render number of pages based on 'items per page' and the Count() of products in the @Model:

@model IPagedList<Product>

//foreach loop that renders the @Model

//Code that displays the pagination using PagedList
<div style="text-align:center">
    @Html.PagedListPager(Model, page => Url.Action("List", new { page = page, category =  ViewBag.CurrentCategory }), PagedListRenderOptions.OnlyShowFivePagesAtATime
    )
</div>

回答1:


I had the exactly same problem and I ended up using StaticPagedList. You can do something like this

public ViewResult List(int page =1, string category =null)
{
    if (category != null) this.CurrentCategory = category;

    var products = repository.Products
                   .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory)
                   .OrderBy(p => p.ProductID)
                   .Skip((page -1) * PageSize)
                   .Take(PageSize);

var count = repository.Products
                   .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory).Count();

var resultAsPagedList = new StaticPagedList<Product>(products, page, PageSize, count);

    return View(resultAsPagedList);
}

as for the view, you just need to replace the model type

@model StaticPagedList<Product>



回答2:


ToPagedList uses Take and Skip internally and when you use the extension to the IQueryable<T> class, that will result in the database query you require. It also retrieves the TotalItemCount into its Metadata.

Sometimes you may need to bring the query results into memory because you are using a method that cannot be translated into sql. That means you have to convert the PagedList back to an Enumerable. You can get around this problem by using the StaticPagedList method like this:

   var superset= repository.Products
      .Where(p => this.CurrentCategory == null 
             || p.Category == this.CurrentCategory)
      .OrderBy(p => p.ProductID)
      .ToPagedList(page, PageSize);

   var subset = superset
      .AsEnumerable()
      .Select(p => new ProductViewModel
      {
          OtherData = p.UntranslateableMethod()  
      })

    var model = new StaticPagedList<ProductViewModel>(subset,
       superset.GetMetaData());
}

From the summary of the method in comments:

Initializes a new instance of the PagedList.StaticPagedList class that contains the already divided subset and information about the size of the superset and the subset's position within it.




回答3:


You will still likely have to ask for a count separately.

var products = repository.Products
                         .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory);
var numProds = products.Count();
var mypage = products.OrderBy(p => p.ProductID)
                     .Skip((page -1) * PageSize)
                     .Take(PageSize);



回答4:


If you use PagedList's methods, you do not need to also use LINQ .skip() and .take(). If you do, then you are pre-limiting the list, and it would be pointless to use the library because you are first filtering down the list to get pagesize results by .skip() and .take() then passing those pagesize results to be filtered again down to pagesize, which will of course be the same, but then PagedList doesn't know what the total is.

If you want to ensure you are not loading all results, simply send an IQueryable to PagedList instead of an Enumerable or List. PagedList will add the .Skip() and .Take() for you, and your database will only return those results.




回答5:


The above explanation is correct. But when you are assigning Static select list..

new StaticPagedList<Product>(products, page, PageSize, count);.

It displays less number of page link from actual count. If Count is 10 it show only 2 pages if your page size is 5..

If you want to show all pages link availabe in count, then

pass count*5 ie count*pagesize

new StaticPagedList<Product>(products, page, PageSize, count*5);//in my case page size is 5

or new StaticPagedList(products, page, PageSize, count*pagesize);

thus it provide all available counts in pages.



来源:https://stackoverflow.com/questions/19942395/pagedlist-using-linq-skip-and-take-but-show-paging-using-count-of-results

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