问题
I have written a simple httprequest/response code and I am getting this below error. I have referenced httpclient, httpcore, common-codecs and common-logging in my classpath. I am very new to java and have no clue what is going on here. Please help me.
Code:
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.HttpResponse;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.Header;
import org.apache.http.HttpHeaders;
public class UnshorteningUrl {
public static void main(String[] args) throws Exception
{
HttpGet request=null;
HttpClient client = HttpClientBuilder.create().build();
try {
request = new HttpGet("trib.me/1lBFzSi");
HttpResponse httpResponse=client.execute(request);
Header[] headers = httpResponse.getHeaders(HttpHeaders.LOCATION);
// Preconditions.checkState(headers.length == 1);
String newUrl = headers[0].getValue();
System.out.println("new url" + newUrl);
} catch (IllegalArgumentException e) {
// TODO: handle exception
}finally {
if (request != null) {
request.releaseConnection();
}
}
}}
Error:
Exception in thread "main" org.apache.http.client.ClientProtocolException
at org.apache.http.impl.client.InternalHttpClient.doExecute(InternalHttpClient.java:186)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:82)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:106)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:57)
at UnshorteningUrl.main(UnshorteningUrl.java:26)
Caused by: org.apache.http.ProtocolException: Target host is not specified
at org.apache.http.impl.conn.DefaultRoutePlanner.determineRoute(DefaultRoutePlanner.java:69)
at org.apache.http.impl.client.InternalHttpClient.determineRoute(InternalHttpClient.java:124)
at org.apache.http.impl.client.InternalHttpClient.doExecute(InternalHttpClient.java:183)
... 4 more
回答1:
The error message is kind of misleading. You've provided a value that does not represent a complete URI
request = new HttpGet("trib.me/1lBFzSi");
It's missing a protocol.
Simply provide a complete URI
request = new HttpGet("http://trib.me/1lBFzSi");
回答2:
This error is probably caused by the wrong url. Check the url:
- protocal missing;
- url parameters encode;
来源:https://stackoverflow.com/questions/24985771/org-apache-http-protocolexception-target-host-is-not-specified