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LeetCode Top Interview Questions 334. Increasing Triplet Subsequence (Java版; Medium)
题目描述
Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Note: Your algorithm should run in O(n) time complexity and O(1) space complexity.
Example 1:
Input: [1,2,3,4,5]
Output: true
Example 2:
Input: [5,4,3,2,1]
Output: false
第一次做; 参考题解, 核心: 找到最小的, 次小的, 次次小的
//找到最小的, 次小的, 次次小的
class Solution {
public boolean increasingTriplet(int[] nums) {
int small=Integer.MAX_VALUE, medium=Integer.MAX_VALUE;
for(int i=0; i<nums.length; i++){
int cur = nums[i];
// cur <= small
if(cur <= small)
small = cur;
// small < cur <= medium
else if(cur<=medium)
medium = cur;
// cur > medium
else
return true;
}
return false;
}
}
优秀解释
来源:CSDN
作者:littlehaes
链接:https://blog.csdn.net/littlehaes/article/details/104105918