Screen Scraping | 易学教程

问题

Hi I'm trying to implement a screen scraping scenario on my website and have the following set so far. What I'm ultimately trying to do is replace all links in the $results variable that have "ResultsDetails.aspx?" to "results-scrape-details/" then output again. Can anyone point me in the right direction?

<?php 
$url = "http://mysite:90/Testing/label/stuff/ResultsIndex.aspx";
$raw = file_get_contents($url);
$newlines = array("\t","\n","\r","\x20\x20","\0","\x0B");
$content = str_replace($newlines, "", html_entity_decode($raw));
$start = strpos($content,"<div id='pageBack'");
$end = strpos($content,'</body>',$start) + 6;
$results = substr($content,$start,$end-$start);
$pattern = 'ResultsDetails.aspx?';
$replacement = 'results-scrape-details/';
preg_replace($pattern, $replacement, $results);
echo $results;

回答1:

Use a DOM tool like PHP Simple HTML DOM. With it you can find all the links you're looking for with a Jqueryish syntax.

// Create DOM object from HTML source
$dom = file_get_html('http://www.domain.com/path/to/page');
// Iterate all matching links
foreach ($dom->find('a[href^=ResultsDetails.aspx') as $node) {
    // Replace href attribute value
    $node->href = 'results-scrape-detail/';
}
// Output modified DOM
echo $dom->outertext;

回答2:

The ? char has special meaning in regexes - either escape it and use the same code or replace the preg_replace with str_ireplace() (I'd recommend the latter approach as it is also more efficient).

(and should the html_entity_decode call really be there?)

来源：https://stackoverflow.com/questions/2846850/screen-scraping

标签

php

screen

screen-scraping