问题
Is there a way to dynamically set the value of the *ngTemplateOutlet directive?
Something along those lines:
<div *ngFor="let item of [ 'div', 'span' ]">
<ng-container *ngTemplateOutlet="{{ item }}"></ng-container>
</div>
<ng-template #div>
<div>some text inside a div</div>
</ng-template>
<ng-template #span>
<span>some text inside a span</span>
</ng-template>
Of course it doesn't work but I guess it explains quite well what I'm trying to achieve: if the item is "div", then it should display the #div template, if it's "span" the #span one.
回答1:
Just point ngTemplateOutlet
at a variable that is a TemplateRef
:
In HTML:
<button (click)="toggleTemplateSelected()">Toggle Template</button>
<br />
<p>Showing
<span class='viewType' *ngIf="showViewTemplate">C</span>
<span class='viewType' *ngIf="!showViewTemplate">C2</span>
template:</p>
<ng-container *ngTemplateOutlet='liveTemplate'></ng-container>
<!--Templates: -->
<ng-template #tmplC>
Hello from TemplateC
</ng-template>
<ng-template #tmplC2>
Hello from TemplateC2
</ng-template>
In code:
@ViewChild('tmplC') tmplC: TemplateRef<any>;
@ViewChild('tmplC2') tmplC2: TemplateRef<any>;
showViewTemplate = true;
liveTemplate: TemplateRef<any>;
toggleTemplateSelected() {
this.showViewTemplate = !this.showViewTemplate;
this.liveTemplate = this.showViewTemplate ? this.tmplC : this.tmplC2;
}
You could also point ngTemplateOutlet
at a function that returns a TemplateRef
.
回答2:
Wrap item in parenthesis to get it to evaluate as an expression. *ngTemplateOutlet="(item.ref)"
If that doesn't work, do let item of [ { ref: 'div' }, { ref: 'span'} ]
and use *ngTemplateOutlet="item.ref"
Similar to Can't get ngTemplateOutlet to work
来源:https://stackoverflow.com/questions/43577481/dynamic-ngtemplateoutlet-value