How to extract a subvector (of an Eigen::Vector) from a vector of indices in Eigen?

问题

Suppose I have

Eigen::VectorXd x; //{1,2,3,4,5,6,7,8}

and

Eigen::VectorXd ind_vec; //{0,2,4,5}

Is there a way an easy way to extract the ind_vec elements of x?

Something like:

x.extract(ind_vec) returning {1, 3, 5, 6}

回答1:

Since the current answer was not satisfactory for me, I googled a bit and I found this tutorial in the Eigen documentation.

#include <Eigen/Dense>
#include <iostream>
using namespace std;
int main()
{
  Eigen::ArrayXf v(6);
  v << 1, 2, 3, 4, 5, 6;
  cout << "v.head(3) =" << endl << v.head(3) << endl << endl;
  cout << "v.tail<3>() = " << endl << v.tail<3>() << endl << endl;
  v.segment(1,4) *= 2;
  cout << "after 'v.segment(1,4) *= 2', v =" << endl << v << endl;
}

Will output:

v.head(3) =
1
2
3

v.tail<3>() = 
4
5
6

after 'v.segment(1,4) *= 2', v =
 1
 4
 6
 8
10
 6

I haven't tested it with vectors, but I guess should be possible as well.

回答2:

Seems like it'd be easy to write yourself if it's just for vectors:

#include "Eigen/Core"

template <typename T, typename T2>
T extract(const T2& full, const T& ind)
{
    int num_indices = ind.innerSize();
    T target(num_indices);
    for (int i = 0; i < num_indices; i++)
    {
        target[i] = full[ind[i]];
    }
    return target;
}

int main()
{
    Eigen::VectorXd full(8); 
    full << 1, 2, 3, 4, 5, 6, 7, 8;
    Eigen::Vector4d ind_vec(4);
    ind_vec << 0, 2, 4, 5;
    std::cout << "full:" << full<< std::endl;
    std::cout << "ind_vec:" << ind_vec<< std::endl;
    std::cout << "extracted" << extract(full,ind_vec) << std::endl;
}

That should work for most cases

edit: for cases where your index scalar type is different than your source and target scalar type the following will work (for all build-in Eigen types).

template <typename T, typename T2>
Eigen::Matrix<typename T2::Scalar,T::RowsAtCompileTime,T::ColsAtCompileTime,T::Options> 
extract2(const Eigen::DenseBase<T2>& full, const Eigen::DenseBase<T>& ind)
{
    using target_t = Eigen::Matrix < T2::Scalar, T::RowsAtCompileTime, T::ColsAtCompileTime, T::Options > ;
    int num_indices = ind.innerSize();
    target_t target(num_indices);
    for (int i = 0; i < num_indices; i++)
    {
        target[i] = full[ind[i]];
    }
    return target;
}

(this is different from the other one in that you can use a vector of ints as indices and a vector of doubles as source and get a vector of doubles returned instead of a vector of ints as extract() above would do)

回答3:

In C++ 11 (and up) do this:

 ind_vec.unaryExpr(x);

You can make use of unaryExpr(Functor) since we are taking an index array and applying a functor to each element of the array. The result type will have the same dimensions as the index array. For the functor, we need an object with an operator:

 Scalar operator() (Index index) const {
     return x[index];
 }

As it happens, Eigen::Matrix has just such an operator already. Here's a full example:

Eigen::VectorXd x(8);  x << 1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8;
Eigen::Array4i ind_vec(0,2,4,5);

// result has dimensions as ind_vec matrix/array, and scalar type from x
Eigen::Array4d result = ind_vec.unaryExpr(x);

std::cout << "result^T = " << result.transpose() << std::endl;

// Output:
// result^T = 1.1 3.3 5.5 6.6

The only caveat is that this requires at least C++11 to work. The problem is that eigen internally relies upon std::result_of to get the scalar result type. Without that, you might get errors stating that a cast is required.

来源：https://stackoverflow.com/questions/26267194/how-to-extract-a-subvector-of-an-eigenvector-from-a-vector-of-indices-in-eig

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