问题
So istringstream
copies the contents of a string when initialised, e.g
string moo("one two three four");
istringstream iss(moo.c_str());
I was wondering if there's a way to make std::istringstream
use the given c_str
as its buffer without copying things. This way, it won't have to copy large bits of memory before passing the std::istringstream&
to functions that take istream&
as an argument.
What I've been trying to do is convert some functions which only take std::ifstream&
arguments (they're mostly parsers) into taking istream&
as well. Would I have to make my own istream
subclass for this?
回答1:
It's fairly trivial to write a basic std::streambuf
class that reads from a given memory area. You can then construct an istream
from this and read from that.
initializing a C++ std::istringstream from an in memory buffer?
Note that the lifetime of the buffer pointed to be c_str()
is very limited, though, and there's no guarantee that a call to c_str()
want cause some copying although I don't know of any implementations where it does.
回答2:
Using istringstream
is not a satisfactory solution, because this copies the entire buffer.
A previous answer suggests the deprecated istrstream
, but as this generates warnings and may be removed in future, a better solution is to use boost::iostreams:
boost::iostreams::stream<boost::iostreams::array_source> stream(moo.c_str(), moo.size());
This avoids copying the buffer in the same way istrstream
did, and saves you having to write your own stream class.
回答3:
the deprecated istrstream
supports this feature.
#include <string>
#include <strstream>
using namespace std;
int main(int argc, char* argv[])
{
string moo = "one two three four";
istrstream istr(const_cast<char*>(moo.c_str()),moo.size());
std::string line;
while(!istr.fail() && !istr.eof()){
getline(istr,line,' ');
cout << line << "_";
}
// prints: one_two_three_four_
}
回答4:
There's only a copy because the parameter you pass, a const char*
, requires conversion to the argument type of the istringstream constructor.
Just pass in the string
without calling c_str()
.
istringstream iss(moo);
Well ok, that doesn't prevent copying completely, but it eliminates an unnecessary copy. To completely eliminate the copy, you'd have to rewrite std::stringbuf, which specifically avoids working directly on the string
you give it.
回答5:
It depends on what a std::string does. According to 27.2.1/1 The class basic_istringstream<charT,traits,Allocator> ... uses a basic_stringbuf<charT,traits,Allocator> object to control the associated storage.
Since the class must use an object it must copy construct the string into that object.
So the real question is not whether a stringstream
copies the contents, but whether copy constructing a string will copy the contents or implement some sort of copy-on-write scheme.
来源:https://stackoverflow.com/questions/3122901/non-copying-istringstream