Calling a constructor of the base class from a subclass' constructor body

问题

I was under impression that it's impossible, see for example: Calling the constructor of the base class after some other instructions in C++
But the following program runs and produces two lines of "Constructor Person":

#include <iostream>

class Person
{
public:
    Person() 
    { 
        std::cout << "Constructor Person" << std::endl; }
    };

class Child : public Person
{
public:
    Child() 
    { 
        c = 1; 
        Person(); 
    }
    int c;
};

int main() 
{
    Child child;
    return 0;
}

The first one is implicit call of the default constructor, that's clear. What about the 2nd one - does it mean that the action described in the title is legitimate? I use Visual C++ 2010.

回答1:

The call inside the child class constructor is not calling the base class constructor, it is creating a temporary, unnamed and new object of type Person. It will be destroyed as the constructor exits. To clarify, your example is the same as doing this:

Child() { c = 1; Person tempPerson; }

Except in this case, the temporary object has a name.

You can see what I mean if you modify your example a little:

class Person
{
public:
    Person(int id):id(id) { std::cout << "Constructor Person " << id << std::endl; }
    ~Person(){ std::cout << "Destroying Person " << id << std::endl; }
    int id;
};

class Child : public Person
{
public:
    Child():Person(1) { c = 1; Person(2); }
int c;
};

int main() {
Child child;

Person(3);
return 0;
}

This produces the output:

Constructor Person 1
Constructor Person 2
Destroying Person 2
Constructor Person 3
Destroying Person 3
Destroying Person 1

回答2:

You can't call it from the body of the child constructor, but you can put it into the initializer list:

public:
    Child() : Person() { c = 1; }

Of course it's not helpful to call the default constructor of the parent because that will happen automatically. It's more useful if you need to pass a parameter to the constructor.

The reason you can't call the constructor from the body is because C++ guarantees the parent will be finished constructing before the child constructor starts.

回答3:

The following is an excerpt from "Accelerated C++": "Derived objects are constructed by:
1. Allocating space for the entire object (base class members as well as derived class members);
2. Calling the base-class constructor to initialize the base-class part of the object;
3. Initializing the members of the derived class as directed by the constructor initializer;
4. Executing the body of the derived-class constructor, if any."

Summarizing the answers and comments: Calling a constructor of the base class from a subclass' constructor body is impossible in the sense that #2 above must precede #4. But we still can create a base object in the derived constructor body thus calling a base constructor. It will be an object different from the object being constructed with the currently executed derived constructor.

来源：https://stackoverflow.com/questions/21395395/calling-a-constructor-of-the-base-class-from-a-subclass-constructor-body

标签

c++

constructor

base-class