问题
Why does the following bit of code work in C:
int res = pow(2, 3);
printf("%d\n", res);
while this other doesn't?
int a = 2;
int b = 3;
int res = pow(a, b);
printf("%d\n", res);
Even if I try
double a = 2;
double b = 3;
double res = pow(a, b);
printf("%f\n", res);
I get an
undefined reference to `pow'
What am I doing wrong?
回答1:
When it works, it's because the calculation was done by the compiler itself (and included in the binary as if you wrote it out)
printf("8\n");
When it doesn't work, is because the pow
function is included in the math library and the math library isn't linked with your binary by default.
To get the math library to be linked, if your compiler is gcc, use
gcc ... -lm ...
With other compilers, should be the same :)
but read the documentation
回答2:
undefined reference to 'pow'
sounds like a linker error. You are not linking in the math library, even if you introduce the function pow
by including <math.h>
.
With gcc, use the -lm
command line parameter to link in the math lib.
回答3:
Use like this
#include <math.h>
#include <stdio.h>
int main(void)
{
for(int i = 1; i < 5; i++)
printf("pow(3.2, %d) = %lf\n", i, pow(3.2, i));
return 0;
}
Output:
pow(3.2, 1) = 3.200000
回答4:
undefined reference to `pow'
because power to any number must have an integer value as power
pow(x,y)
where, x must be real and y must be a whole number
来源:https://stackoverflow.com/questions/4174080/using-pow-function-throws-undefined-reference-error-in-c