问题
I know I can do this:
set=("1 2 3" "4 5 6")
for subset in "${set[@]}"
do
for element in $subset
do
echo $element
done
done
1 2 3 4 5 6 will be printed sequentially. However, I can not do this:
set="(1 2 3) (4 5 6)"
for subset in $set
do
echo ${subset[2]}
done
I want to print 3 6. The reason why I want to do this is that I want to have access to whichever element I want to access during iteration instead of iterating one by one. That's why I try to put arrays inside quotes instead of putting quotes inside a big array. Is there any way to do this? Thanks,
回答1:
Unfortunately, I don't think bash supports multi-dimentional arrays, which sounds like what you're looking for. You can simulate it with a little help from bash itself like so:
x=()
x+=("1,2,3")
x+=("4,5,6")
for val in ${x[@]}; do
subset=($(echo $val | tr ',' ' '))
echo ${subset[2]}
done
来源:https://stackoverflow.com/questions/19919652/in-bash-is-it-possible-to-put-several-arrays-inside-quotes-and-then-access-them