Calculating Great-Circle Distance with SQLite

依然范特西╮ 提交于 2019-11-27 13:17:40

问题


Here is my problem, I have a SQLite table with locations and latitudes / longitudes. Basically I need to:

SELECT location, HAVERSINE(lat, lon) AS distance FROM location ORDER BY distance ASC;

HAVERSINE() is a PHP function that should return the Great-Circle Distance (in miles or km) given a pair of latitude and longitude values. One of these pairs should be provided by PHP and the other pair should be provided by each latitude / longitude row available in the locations table.

Since SQLite doesn't has any Geo Spatial extension (AFAIK SpatiaLite exists but still...) I'm guessing the best approach would be to use a custom function with either one of the PDO methods:

  • PDO::sqliteCreateFunction()
  • PDO::sqliteCreateAggregate()

I think for this case PDO::sqliteCreateFunction() would be enough, however my limited experience with this function can be reduced to usage cases similar to the one provided in the PHP Manual:

$db = new PDO('sqlite:geo.db');

function md5_and_reverse($string) { return strrev(md5($string)); }

$db->sqliteCreateFunction('md5rev', 'md5_and_reverse', 1);
$rows = $db->query('SELECT md5rev(filename) FROM files')->fetchAll();

I'm having some trouble figuring out how can I get an SQLite user defined function to process data from PHP and table data at the same time and I would appreciate if someone could help me solve this problem while also understanding SQLite UDFs (a big win of SQLite IMO) a little bit better.

Thanks in advance!


回答1:


From your "interesting link".

function sqlite3_distance_func($lat1,$lon1,$lat2,$lon2) {
    // convert lat1 and lat2 into radians now, to avoid doing it twice below
    $lat1rad = deg2rad($lat1);
    $lat2rad = deg2rad($lat2);
    // apply the spherical law of cosines to our latitudes and longitudes, and set the result appropriately
    // 6378.1 is the approximate radius of the earth in kilometres
    return acos( sin($lat1rad) * sin($lat2rad) + cos($lat1rad) * cos($lat2rad) * cos( deg2rad($lon2) - deg2rad($lon1) ) ) * 6378.1;
}

$db->sqliteCreateFunction('DISTANCE', 'sqlite3_distance_func', 4);

Then do a query with:

"SELECT * FROM location ORDER BY distance(latitude,longitude,{$lat},{$lon}) LIMIT 1"

EDIT (by QOP): I finally needed this again and this solution worked out great, I just ended up modifying the code a bit to it is a bit less verbose and handles non-numeric values gracefully, here it is:

$db->sqliteCreateFunction('distance', function () {
    if (count($geo = array_map('deg2rad', array_filter(func_get_args(), 'is_numeric'))) == 4) {
        return round(acos(sin($geo[0]) * sin($geo[2]) + cos($geo[0]) * cos($geo[2]) * cos($geo[1] - $geo[3])) * 6378.14, 3);
    }

    return null;
}, 4);



回答2:


So far I could only think of this solution:

$db = new PDO('sqlite:geo.db');

$db->sqliteCreateFunction('ACOS', 'acos', 1);
$db->sqliteCreateFunction('COS', 'cos', 1);
$db->sqliteCreateFunction('RADIANS', 'deg2rad', 1);
$db->sqliteCreateFunction('SIN', 'sin', 1);

And then execute the following lengthy query:

SELECT "location",
       (6371 * ACOS(COS(RADIANS($latitude)) * COS(RADIANS("latitude")) * COS(RADIANS("longitude") - RADIANS($longitude)) + SIN(RADIANS($latitude)) * SIN(RADIANS("latitude")))) AS "distance"
FROM "locations"
HAVING "distance" < $distance
ORDER BY "distance" ASC
LIMIT 10;

If anyone can think of a better solution please let me know.


I just found this interesting link, I'll try it tomorrow.




回答3:


Building off Alix's answer...

$db->sqliteCreateFunction('HAVERSINE', 'haversine', 2);

I would imagine that this would allow the query that you specified in your question to work.



来源:https://stackoverflow.com/questions/2083182/calculating-great-circle-distance-with-sqlite

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!