问题
According to the docs it should work to combine @property
and @abc.abstractmethod
so the following should work in python3.3:
import abc
class FooBase(metaclass=abc.ABCMeta):
@property
@abc.abstractmethod
def greet(self):
""" must be implemented in order to instantiate """
pass
@property
def greet_comparison(self):
""" must be implemented in order to instantiate """
return 'hello'
class Foo(FooBase):
def greet(self):
return 'hello'
test the implementation:
In [6]: foo = Foo()
In [7]: foo.greet
Out[7]: <bound method Foo.greet of <__main__.Foo object at 0x7f935a971f10>>
In [8]: foo.greet()
Out[8]: 'hello'
so it is obviously not a property, because then it should work like that:
In [9]: foo.greet_comparison
Out[9]: 'hello'
Maybe I'm to stupid or it simply doesn't work, somebody has an idea?
回答1:
If you want greet
to be a property, you still need to use the @property
decorator in your implementation:
class Foo(FooBase):
@property
def greet(self):
return 'hello'
All that an ABC metaclass does is test wether or not you have provided the same name in the concrete class; it doesn't care if it is a method or a property or a regular attribute.
Because it doesn't care, it doesn't magically apply property
decorators either. This is a good thing; perhaps in a specific implementation a static attribute is enough to satisfy the requirement, and a property would be overkill.
The purpose of a ABC metaclass is to help you detect gaps in your implementation; it never was intended to enforce the types of the attributes.
Note that before Python 3.3 you can not combine a @property
with an @abstractmethod
. You would have to use an @abstractproperty decorator instead. There is an ambiguity there when your property needs more than a simple getter in that case; Python 3.3 covers that case much better (see issue 11610 for the painful details).
来源:https://stackoverflow.com/questions/14671095/abc-abstractmethod-property