问题
I'm trying out Rhino to embed Javascript in Java. I noticed that when I eval a script that adds two ints together in Javascript, the result comes back as a Double.
ScriptEngine engine = new ScriptEngineManager().getEngineByName("JavaScript");
engine.put("x", 3);
engine.put("y", 4);
assertEquals(3, engine.eval("x")); // OK
assertEquals(4, engine.eval("y")); // OK
assertEquals(7, engine.eval("x + y")); // FAILS, actual = (Double) 7.0
So why does the x + y expression return a double instead of an int?
Is Javascript itself doing some type promotion I don't understand?
回答1:
Fun fact of the day: All numbers in javascript (ECMAScript) are double-precision.
The Number type has exactly 18437736874454810627 (that is, 264−253+3) values, representing the double-precision 64-bit format IEEE 754 values as specified in the IEEE Standard for Binary Floating-Point Arithmetic, except that the 9007199254740990 (that is, 253−2) distinct “Not-a-Number” values of the IEEE Standard are represented in ECMAScript as a single special NaN value.
http://people.mozilla.org/~jorendorff/es6-draft.html#sec-8.1.5
回答2:
JavaScript only has one numerical type - Number which is analogous to the Java Double type. I expect the engine is coercing the type to Number to perform the arithmetic.
来源：https://stackoverflow.com/questions/15528573/rhino-js-scriptengine-from-java-integers-in-doubles-out