Need SQL command that will insert a row after specific row

问题

I need SQL command that will insert a row after specific row. Example:-

Before table

Id.         Name.      
1.           Xyz.          
2.           Xyz
3.           Xyz    

Want result need to add 'Abc' data after each 'xyz' having same id like:-

Id.         Name.      
1.           Xyz.    
1.           Abc      
2.           Xyz
2.           Abc
3.           Xyz
3.           Abc

回答1:

You need UNION ALL:

SELECT t.*
FROM (SELECT id, Name
      FROM table t
      UNION ALL
      SELECT ID, 'Abc'
      FROM table t
    ) t
ORDER BY ID, NAME;

This will not insert row, it just provide you run time view. If you want only insert then you need to truncate your table (note : take a backup of current table ) & perform insert operation.

回答2:

INSERT INTO your_table 
SELECT Id
       ,'Abc' AS Name
FROM your_table
Where Name = 'Xyz'

I am not sure if OVERRIDING SYSTEM VALUE is needed, it depends on your table. But this query should do what you need. It will get all the rows that contain the Xyz value and use the same id and a different name. Then if you order by Id because remember ordering is never guaranteed if you don't use order by

回答3:

Try this

START TRANSACTION;

UPDATE table_sample SET column = column+1 WHERE column >= some_value_here ";

INSERT INTO table_sample (id, column_name) VALUES
(NULL, 'value_here');

COMMIT;

来源：https://stackoverflow.com/questions/55122499/need-sql-command-that-will-insert-a-row-after-specific-row