问题
I'm currently looking for on how to determine the CRC produced from the machine to PC (and vice-versa). The devices are communicating using serial communication or RS232 cable.
I do only have data to be able for us to create a program to be used for both devices.
The data given was from my boss and the program was corrupted. So we are trying for it to work out.
I hope everyone can help.
Thanks :)
回答1:
The sequence to use for the CRC calculation in your protocol is the ASCII string
- starting from the first printing character (e.g. the 'R' from REQ)
- until and including the '1E' in the calculation.
It's a CRC with the following specs according to our CRC calculator
CRC:16,1021,0000,0000,No,No
which means:
CRC width: 16 bit (of course)
polynomial: 1021 HEX (truncated CRC polynomial)
init value: 0000
final Xor applied: 0000
reflectedInput: No
reflectedOutput: No`
(If 'init value' were FFFF, it would be a "16 bit width CRC as designated by CCITT").
See also the Docklight CRC glossary and the Boost CRC library on what the CRC terms mean plus sample code.
What I did is to write a small script that tries out the popular 16 bit CRCs on varying parts of the first simple "REQ=INI" command, and see if I end up with a sum of 4255. This failed, but instead of going a full brute force with trying all sorts of polynoms, I assumed that it was maybe just an oddball / flawed implementation of the known standards, and indeed succeeded with a variation of the CRC-CCITT.
Heres is some slow & easy C code (not table based!) to calculate all sorts of CRCs:
// Generic, not table-based CRC calculation
// Based on and credits to the following:
// CRC tester v1.3 written on 4th of February 2003 by Sven Reifegerste (zorc/reflex)
unsigned long reflect (unsigned long crc, int bitnum) {
// reflects the lower 'bitnum' bits of 'crc'
unsigned long i, j=1, crcout=0;
for (i=(unsigned long)1<<(bitnum-1); i; i>>=1) {
if (crc & i) crcout|=j;
j<<= 1;
}
return (crcout);
}
calcCRC(
const int width, const unsigned long polynominal, const unsigned long initialRemainder,
const unsigned long finalXOR, const int reflectedInput, const int reflectedOutput,
const unsigned char message[], const long startIndex, const long endIndex)
{
// Ensure the width is in range: 1-32 bits
assert(width >= 1 && width <= 32);
// some constant parameters used
const bool b_refInput = (reflectedInput > 0);
const bool b_refOutput = (reflectedOutput > 0);
const unsigned long crcmask = ((((unsigned long)1<<(width-1))-1)<<1)|1;
const unsigned long crchighbit = (unsigned long)1<<(width-1);
unsigned long j, c, bit;
unsigned long crc = initialRemainder;
for (long msgIndex = startIndex; msgIndex <= endIndex; ++msgIndex) {
c = (unsigned long)message[msgIndex];
if (b_refInput) c = reflect(c, 8);
for (j=0x80; j; j>>=1) {
bit = crc & crchighbit;
crc<<= 1;
if (c & j) bit^= crchighbit;
if (bit) crc^= polynominal;
}
}
if (b_refOutput) crc=reflect(crc, width);
crc^= finalXOR;
crc&= crcmask;
return(crc);
}
With this code and the CRCs specs listed above, I have been able to re-calculate the following three sample CRCs:
10.03.2014 22:20:57.109 [TX] - REQ=INI<CR><LF>
<RS>CRC=4255<CR><LF>
<GS>
10.03.2014 22:20:57.731 [TX] - ANS=INI<CR><LF>
STATUS=0<CR><LF>
<RS>CRC=57654<CR><LF>
<GS>
10.03.2014 22:20:59.323 [TX] - ANS=INI<CR><LF>
STATUS=0<CR><LF>
MID="CTL1"<CR><LF>
DEF="DTLREQ";1025<CR><LF>
INFO=0<CR><LF>
<RS>CRC=1683<CR><LF>
<GS>
I failed on the very complex one with the DEF=
parts - probably didn't understand the character sequence correctly.
The Docklight script I used to reverse engineer this:
Sub crcReverseEngineer()
Dim crctypes(7)
crctypes(0) = "CRC:16,1021,FFFF,0000" ' CCITT
crctypes(1) = "CRC:16,8005,0000,0000" ' CRC-16
crctypes(2) = "CRC:16,8005,FFFF,0000" ' CRC-MODBUS
' lets try also some nonstandard variations with different init and final Xor, but stick
' to the known two polynoms.
crctypes(3) = "CRC:16,1021,FFFF,FFFF"
crctypes(4) = "CRC:16,1021,0000,FFFF"
crctypes(5) = "CRC:16,1021,0000,0000"
crctypes(6) = "CRC:16,8005,FFFF,FFFF"
crctypes(7) = "CRC:16,8005,FFFF,0000"
crcString = "06 1C 52 45 51 3D 49 4E 49 0D 0A 1E 43 52 43 3D 30 30 30 30 0D 0A 1D"
For reflectedInOrOut = 0 To 3
For cType = 0 To 7
crcSpec = crctypes(cType) & "," & IIf(reflectedInOrOut Mod 2 = 1, "Yes", "No") & "," & IIf(reflectedInOrOut > 1, "Yes", "No")
For cStart = 1 To 3
For cEnd = 9 To (Len(crcString) + 1) / 3
subDataString = Mid(crcString, (cStart - 1) * 3 + 1, (cEnd - cStart + 1) * 3)
result = DL.CalcChecksum(crcSpec, subDataString, "H")
resultInt = CLng("&h" + Left(result, 2)) * 256 + CLng("&h" + Right(result, 2))
If resultInt = 4255 Then
DL.AddComment "Found it!"
DL.AddComment "sequence: " & subDataString
DL.AddComment "CRC spec: " & crcSpec
DL.AddComment "CRC result: " & result & " (Integer = " & resultInt & ")"
Exit Sub
End If
Next
Next
Next
Next
End Sub
Public Function IIf(blnExpression, vTrueResult, vFalseResult)
If blnExpression Then
IIf = vTrueResult
Else
IIf = vFalseResult
End If
End Function
Hope this helps and I'm happy to provide extra information or clarify details.
来源:https://stackoverflow.com/questions/22219796/crc-reverse-engineer-checksum-from-machine-pc