题目
请判断一个链表是否为回文链表。
解题思路
反转链表的后半段。
C++代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool isPalindrome(ListNode* head) {
if(head == NULL || head->next == NULL)
return true;
ListNode* slow = head;
ListNode* fast = head;
while(fast->next)
{
slow = slow->next;
fast = fast->next;
if(fast->next)
fast = fast->next;
}
fast = slow->next;
slow->next = NULL;
while(fast)
{
ListNode *p = fast->next;
fast->next = slow;
slow = fast;
fast = p;
}
fast = slow;
slow = head;
while(slow && fast)
{
if(slow->val != fast->val)
return false;
fast = fast->next;
slow = slow->next;
}
return true;
}
};