HttpClient: how do I obtain the underlying socket from an existing connection?

落爺英雄遲暮 提交于 2020-01-13 16:30:12

问题


I am using HttpClient 4.02 to create a connection via proxy (using the CONNECT method) to tunnel a connection to a remote server. HttpClient is very convenient for this but I am new to the API and cannot see how to get at the underlying Socket of the tunneled connection.

The following code taken from: http://svn.apache.org/repos/asf/httpcomponents/httpclient/tags/4.0.1/httpclient/src/examples/org/apache/http/examples/client/ClientExecuteProxy.java

    // make sure to use a proxy that supports CONNECT
    HttpHost target = new HttpHost("target.server.net", 443, "https");
    HttpHost proxy = new HttpHost("some.proxy.net", 8080, "http");

    // general setup
    SchemeRegistry supportedSchemes = new SchemeRegistry();

    // Register the "http" and "https" protocol schemes, they are
    // required by the default operator to look up socket factories.
    supportedSchemes.register(new Scheme("http", 
            PlainSocketFactory.getSocketFactory(), 80));
    supportedSchemes.register(new Scheme("https", 
            SSLSocketFactory.getSocketFactory(), 443));

    // prepare parameters
    HttpParams params = new BasicHttpParams();
    HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);

    ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, 
            supportedSchemes);

    DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params);

    httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy);

    HttpGet req = new HttpGet("/");

    System.out.println("executing request to " + target + " via " + proxy);
    HttpResponse rsp = httpclient.execute(target, req);
    HttpEntity entity = rsp.getEntity();

This sets up the connection nicely but is there a way to get at the underlying Socket in order for me to use a custom protocol to talk to the server at target.server.net?


回答1:


Open a change request in the project's JIRA. This feature simply got overlooked. While it should be fairly trivial to put together an equivalent of ProxyClient from 3.x, it makes sense to ship one with the stock version of HttpClient.

Edit:

Available since version 4.2. See http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/impl/client/ProxyClient.html




回答2:


Not sure I completely understand your requirements, but I'll give it my best shot...

Try this: http://svn.apache.org/viewvc/httpcomponents/oac.hc3x/trunk/src/examples/ProxyTunnelDemo.java?view=markup




回答3:


In a comment, @willjcroz says:

It is so that my app is usable for people behind firewalls where the only way out would be a web proxy. By connecting to the proxy it will forward data to the target server as HTTPS, giving a secure connection to the target server.

If you are going to successfully tunnel your protocol through web proxies, protocol aware firewalls and so on, the client and server sides of your application have to conform to the HTTP protocol specifications. If you (somehow) managed to drill down to the socket level, the chances are that you would violate the protocol ...

Instead, you should implement your custom protocol by putting your data in the content of the HTTP requests and responses, using custom HTTP headers in messages / responses, custom content types, and so on.



来源:https://stackoverflow.com/questions/3741417/httpclient-how-do-i-obtain-the-underlying-socket-from-an-existing-connection

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