问题
Select * from concat(YEAR(DATE_SUB(MAX(Column_name),60),MONTH(DATE_SUB(MAX(Column_name),60),-01)
The month()
yields only single digit for months until September i.e Jan returns 1
instead of 01
. Need help in handling this.
I am using this output to feed to another SELECT
query using TO_DATE
.
回答1:
month()
function returns integer, that is why there is no leading zero. You can use lpad(month,2,0)
function to format month:
hive> select lpad(month('2017-09-01'),2,0);
OK
09
Time taken: 0.124 seconds, Fetched: 1 row(s)
hive> select lpad(month('2017-10-01'),2,0);
OK
10
Time taken: 0.433 seconds, Fetched: 1 row(s)
Alternatively you can use substr()
to extract year and month from the date:
hive> select substr('2017-10-01',1,4) as year, substr('2017-10-01',6,2) as month;
OK
year month
2017 10
date_sub() function prior to Hive 2.1.0 (HIVE-13248) return type was a String because no Date type existed when the method was created. See here: https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF
来源:https://stackoverflow.com/questions/46658193/month-in-mm-using-month-in-hive