问题
My string is $text1 = 'A373R12345'
I want to find last none digital number occurrence of this string.
So I use this regular expression ^(.*)[^0-9]([^-]*)
Then I got this result:
1.A373
2.12345
But my expected result is:
1.A373R
(It has 'R')
2.12345
Another example is $text1 = 'A373R+12345'
Then I got this result:
1.A373R
2.12345
But my expected result is:
1.A373R+
(It has '+')
2.12345
I want contain the last none digital number!!
Please help !! thanks!!
回答1:
$text1 = 'A373R12345';
preg_match('/^(.*[^\d])(\d+)$/', $text1, $match);
echo $match[1]; // A373R
echo $match[2]; // 12345
$text1 = 'A373R+12345';
preg_match('/^(.*[^\d])(\d+)$/', $text1, $match);
echo $match[1]; // A373R+
echo $match[2]; // 12345
Explanation of regex broken down:
^ match from start of string
(.*[^\d]) match any amount of characters where the last character is not a digit
(\d+)$ match any digit character until end of string
来源:https://stackoverflow.com/questions/13618077/php-regex-to-match-the-last-occurrence-of-a-string