问题
Let's say I have a UserControl called MyVideoControl located in MainWindow.xaml:
<Window Name="_mainWindow">
<Grid>
<MyVideoControl Name="_localVideo"/>
</Grid>
</Window>
Now a user clicks a button and I want the UserControl to float on top of the MainWindow.xaml, inside a newly created window called PopUp.xaml.
<Window Name="_popUpWindow">
<Grid>
<MyVideoControl Name="_localVideo"/>
</Grid>
</Window>
How do I accomplish this, so the entire object gets moved? Currently I use XAML to declaratively place MyVideoControl inside my windows, but I'm guessing I'll need to do everything programatically?
回答1:
Yes you can do this by removing the userControl
from the Mainwindow
and adding it as a logical child to any of the control in the PopupWin
window.
UserControl.xaml:
<UserControl x:Class="WpfApplication1.UserControl1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="100" d:DesignWidth="100">
<Grid>
<TextBox x:Name="txtBlock1" Text="hai"/>
</Grid>
</UserControl>
MainWindow.xaml :
<Window x:Class="WpfApplication1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:WpfApplication1="clr-namespace:WpfApplication1" Title="MainWindow" Height="550" Width="555">
<Grid>
<StackPanel x:Name="mainPanel" Orientation="Vertical ">
<Button Content="Button" Height="23" Name="button1" Width="75" Click="button1_Click" />
<WpfApplication1:UserControl1 x:Name="myUserControl" />
</StackPanel>
</Grid>
</Window>
PopupWin.xaml :
<Window x:Class="WpfApplication1.PopupWin"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="PopupWin" Height="300" Width="300">
<StackPanel x:Name="mainPanel"/>
</Window>
PopupWin.xaml.cs: Expose a new constructor to accept userControl
and add it as a child to the mainPanel
public partial class PopupWin : Window
{
public PopupWin()
{
InitializeComponent();
}
private UserControl control;
public PopupWin(UserControl control)
: this()
{
this.control = control;
this.mainPanel.Children.Add(this.control);
}
}
MainWindow.xaml.cs On Button_Click remove the userControl from the current MainWindow
and pass it to PopupWin
, in this case via constructor.
private void button1_Click(object sender, RoutedEventArgs e)
{
this.mainPanel.Children.Remove(this.myUserControl);
var wind = new PopupWin(this.myUserControl);
wind.ShowDialog();
}
Note: The userControl
instance should always be a logical child of only one
element at anytime.
回答2:
If you make the UserControl
a resource you can do this.
Example:
App.Xaml
<Application x:Class="WpfApplication10.App"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
StartupUri="MainWindow.xaml">
<Application.Resources>
<ContentControl x:Key="sharedContent">
<Label Content="StackOverFlow" />
</ContentControl>
</Application.Resources>
</Application>
MainWindow
<Window x:Class="WpfApplication10.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="325" Width="422" Name="UI">
<StackPanel>
<Button Content="Open PopUp" Click="Button_Click" />
<ContentControl Content="{DynamicResource sharedContent}" />
</StackPanel>
</Window>
PopUp Window
<Window x:Class="WpfApplication10.PopupWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="PopupWindow" Height="300" Width="300" xmlns:my="clr-namespace:WpfApplication10">
<Grid>
<ContentControl Content="{DynamicResource sharedContent}" />
</Grid>
</Window>
Result:
回答3:
Another way this can be accomplished, using a dynamic layout...
public partial class MainWindow : Window
{
public Button ControlToMove { get; set; }
public MainWindow()
{
InitializeComponent();
//create button
ControlToMove = new Button();
//add text to button
ControlToMove.Content = "Click to move me to pop up window";
//add a new routed event to the buttons click property
ControlToMove.Click += new RoutedEventHandler(MoveControlToPopUp);
//add control to the layout grid
MainGrid.Children.Add(ControlToMove);
}
//This method moves the button to a popup window
private void MoveControlToPopUp(object sender, RoutedEventArgs e)
{
//get the name of the control from sender
var control = sender as Button;
var controlName = control.Name;
//checks to see if this is the control we want moved
//if its not, method exits
if (controlName != ControlToMove.Name) return;
//create copy of the control
var copiedControl = control;
//remove control from existing window
MainGrid.Children.Remove(control);
//create pop up window
var popUpWindow = new PopUpWindow(copiedControl);
popUpWindow.Show();
}
}
public class PopUpWindow : Window
{
public Grid Layout { get; set; }
public PopUpWindow(Button button)
{
//create a grid for the new window
Layout = new Grid();
//add control to grid
Layout.Children.Add(button);
//add grid to window
this.AddChild(Layout);
}
}
}
The only thing I didn't do there was adding the capability to move the button back to main window when it is clicked in the popup window.
来源:https://stackoverflow.com/questions/15891869/how-to-move-wpf-usercontrol-from-one-window-to-another