问题
I have these models:
class App(models.Model):
name = models.CharField(max_length=100)
class ProjectA(models.Model):
name = models.CharField(max_length=100)
app = models.ForeignKey(App)
class ProjectB(ProjectA):
pass
class Attachment(models.Model):
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField()
project = generic.GenericForeignKey("content_type","object_id")
file = models.FileField(upload_to=".")
I'm registering all the models for the admin, and I'm unregistering Group, User and Site. The thing is, when I access the Attachment in the admin, I see it rendered like this:
In the Content type select, I see this list:
The reason Attachment has a GenericForeignKey is because both ProjectA and ProjectB need to access it. I know that ProjectA and ProjectB are identical, but it's a requirement that they are stored in 2 separate tables. How could I made the Attachment class useable from the admin? I know how to use contenttypes from normal views, but from the admin not.
In the Attachment class I would only like to have a select for Project A or Project B, and then a list of all Project A's or all Project B's, followed by the file that I want to attach.
Is such a thing possible from the Admin? Will I need to show the user the Object Id column?
回答1:
if I'm not wrong, you want this. http://code.google.com/p/django-genericadmin/
my advice will work differently. you will add a little more form in ProjectA, ProjectB as inline. in your admin.py
from django.contrib import admin
from django.contrib.contenttypes import generic
from myproject.myapp.models import Attachment, ProjectA, ProjectB
class Attachmentline(generic.GenericTabularInline): #or generic.GenericStackedInline, this has different visual layout.
model = Attachment
class ProjectAdmin(admin.ModelAdmin):
inlines = [
Attachmentline,
]
admin.site.register(ProjectA, ProjectAdmin)
admin.site.register(ProjectB, ProjectAdmin)
go your ProjectA or ProjectB admin and see new admin.
this isn't what you want but it can help you. otherwise you need check first link.
回答2:
You should notice that
" know that ProjectA and ProjectB are identical, but it's a requirement that they are stored in 2 separate tables"
is not really correct. All the data is stored in your app_projecta table, and (only) some pointers are kept in table app_projectb. If you are already going in this path, I would suggest starting with this instead:
class App(models.Model):
name = models.CharField(max_length=100)
class Project(models.Model):
name = models.CharField(max_length=100)
app = models.ForeignKey(App)
class ProjectA(Project):
pass
class ProjectB(Project):
pass
class Attachment(models.Model):
project = models.ForeignKey(Project)
file = models.FileField(upload_to=".")
This already gets you a bit closer to where you want to get...
来源:https://stackoverflow.com/questions/6335565/how-can-i-customize-the-display-of-a-model-using-contenttypes-in-the-admin