问题
I want to catch all Exception from routes.
I add this OnExeption :
onException(Exception.class).process(new MyFunctionFailureHandler()).stop();
Then, I create the class MyFunctionFailureHandler.
public class MyFunctionFailureHandler implements Processor {
@Override
public void process(Exchange exchange) throws Exception {
Throwable caused;
caused = exchange.getProperty(Exchange.EXCEPTION_CAUGHT, Throwable.class);
exchange.getContext().createProducerTemplate().send("mock:myerror", exchange);
}
}
Unfortunately, it doesn't work and I don't know why.
if there is an Exception, the program must stop.
How can I know why this code doesn't work!!
Thanks.
回答1:
I used this on my route:
public class MyCamelRoute extends RouteBuilder {
@Override
public void configure() throws Exception {
from("jms:start")
.process(testExcpProcessor)
// -- Handle Exceptions
.onException(Exception.class)
.process(errorProcessor)
.handled(true)
.to("jms:start");
}
}
and in my errorProcessor
public class ErrorProcessor implements Processor {
@Override
public void process(Exchange exchange) throws Exception {
Exception cause = exchange.getProperty(Exchange.EXCEPTION_CAUGHT, Exception.class);
if(cause != null){
log.error("Error has occurred: ", cause);
// Sending Error message to client
exchange.getOut().setBody("Error");
}else
// Sending response message to client
exchange.getOut().setBody("Good");
}
}
I hope it helps
回答2:
keep in mind that if you have routes in multiple RouteBuilder classes, having an onExcpetion within this route will affect all routes under this RouteBuilder only
review this answer
additionally if an exception occurs within a route and handled inside this route,it won't be propagated to the original caller route you need to use noErrorHandler() i.e. from(direct:start).errorHandler(noErrorHandler())
to propagate the exception handling back to the caller
来源:https://stackoverflow.com/questions/14198043/apache-camel-onexception