问题
Why these lines of code:
if(my_rank != 0) {
sprintf(msg, "Hello from %d of %d...", my_rank, comm_sz);
if(my_rank == 2) {
sleep(2);
sprintf(msg, "Hello from %d of %d, I have slept 2 seconds...", my_rank, comm_sz);
}
MPI_Send(msg, strlen(msg), MPI_CHAR, 0, 0, MPI_COMM_WORLD);
}
else {
printf("Hello from the chosen Master %d\n", my_rank);
for(i = 1; i < comm_sz; i++) {
MPI_Recv(msg, MAX_STRING, MPI_CHAR, i, 0, MPI_COMM_WORLD, MPI_STATUS_IGNORE);
printf("%s\n", msg);
}
}
give this result?
Hello from the chosen Master 0
Hello from 1 of 5...
Hello from 2 of 5, I have slept 2 seconds...
Hello from 3 of 5... have slept 2 seconds...
Hello from 4 of 5... have slept 2 seconds...
Doesn't each process have its copy of 'msg' ?
回答1:
strlen()
does not include the null terminator, hence it will not be sent to the master. Receiving the message from rank 3 will not overwrite the later part of the string, so it is still displayed. You should use strlen(msg) + 1
as send count.
来源:https://stackoverflow.com/questions/44167437/behavior-of-mpi-send-and-mpi-recv