How can fit curve on this log data?

青春壹個敷衍的年華 提交于 2020-01-11 13:08:55

问题


I have a problem with a fit curve on this data:

On x axes we have a data about wind intensity (m/s), on y axes we have log data (fish catch). I fitted a curve (nls model, Gaussian curve) only on data without logaritm, but when i tried on log data, R tell me:

Error in nls(mean.w ~ k * exp(-1/2 * (x.wind - mu)^2/sigma^2),  : 
  singolar gradient

The model is: mean.w ~ k * exp(-1/2 * (x.wind - mu)^2/sigma^2), where k,mu and sigma are the parameters to estimate, and

mean.w # is y axes (log fish catch) 
x.wind # is x axes wind intensity 

the fit curve on not log data is:

# Mean point in red

My aspected result on log data is a similar fit curve, with different values of parameters, the problem is, wath kind of model i must to use?

The data are:

1.1        1.4        1.6        1.7        1.8        1.9          2        2.1        2.2        2.3        2.4        2.5 
-3.0951726        NaN -2.5337439 -3.6184583 -3.2161971 -2.4405031 -1.4349350 -1.5676554 -1.0594076 -0.3290359 -1.2241878 -0.6336298 
       2.6        2.7        2.8        2.9          3        3.1        3.2        3.3        3.4        3.5        3.6        3.7 
-1.3863366 -1.4221593 -1.4961145 -1.2632693 -2.5509134 -4.7270333 -2.4795247 -2.0024069 -4.5975918 -2.9954250 -3.2390678 -2.6339971 
       3.8        3.9          4        4.1        4.2        4.3        4.4        4.5        4.6          5 
-3.3419309 -3.5258236 -4.4962217  0.7027033 -3.6392906 -4.0426306 -1.0798462        NaN -3.0574602 -3.0498198 

With x values from 1.1 to 5, and below log data.


回答1:


The problem is the model itself. The RHS of the model can be written:

k * exp(-1/2 * x.wind / sigma^2) * exp(1/2 * mu /sigma^2)

so k and the rightmost factor play the same role. The parameters are not uniquely determined.

To fix this omit k or the last factor from the model.



来源:https://stackoverflow.com/questions/40969813/how-can-fit-curve-on-this-log-data

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