Python error os.walk IOError

问题

I tried to track the file with server in the filename and i can print all the file in directory with server** but when I try to read the file it gives me error" saying:

Traceback (most recent call last):
  File "view_log_packetloss.sh", line 27, in <module>
    with open(filename,'rb') as files:
IOError: [Errno 2] No such file or directory: 'pcoip_server_2014_05_19_00000560.txt'

I have seen similar question being asked but I could not fix mine, some error were fixed using chdir to change the current directory to the file directory. Any help is appreciated. Thank you

#!usr/bin/env/ python
import sys, re, os

#fucntion to find the packetloss data in pcoip server files
def function_pcoip_packetloss(filename):
        lineContains = re.compile('.*Loss=.*')  #look for "Loss=" in the file
        for line in filename:
                if lineContains.match(line):    #check if line matches "Loss="
                        print 'The file has: '  #prints if "Loss=" is found
                        print line
                        return 0;

for root, dirs, files in os.walk("/users/home10/tshrestha/brb-view/logs/vdm-sdct-agent/pcoip-logs"):
        lineContainsServerFile = re.compile('.*server.*')
        for filename in files:
                if lineContainsServerFile.match(filename):
                        with open(filename,'rb') as files:
                                print 'filename'
                                function_pcoip_packetloss(filename);

回答1:

the files are names of file objects in root directory.

dirpath is a string, the path to the directory. dirnames is a list of the names of the subdirectories in dirpath (excluding '.' and '..'). filenames is a list of the names of the non-directory files in dirpath. Note that the names in the lists contain no path components. To get a full path (which begins with top) to a file or directory in dirpath, do os.path.join(dirpath, name).

try this

for root, dirs, files in os.walk("/users/home10/tshrestha/brb-view/logs/vdm-sdct-agent/pcoip-logs"):
    lineContainsServerFile = re.compile('.*server.*')
    for filename in files:
            if lineContainsServerFile.match(filename):
                    filename = os.path.join(root, filename)
                    with open(filename,'rb') as files:
                            print 'filename:', filename
                            function_pcoip_packetloss(filename);

回答2:

The os.walk() function is a generator of 3-element tuples. Each tuple contains a directory as its first element. The second element is a list of subdirectories in that directory, and the third is a list of the files.

To generate the full path to each file it is necessary to concatenate the first entry (the directory path) and the filenames from the third entry (the files). The most straightforward and platform-agnostic way to do so uses os.path.join().

Also note that it will be much more efficient to use

lineContainsServerFile = re.compile('server')

and lineContainsServerFile.search() rather than trying to match a wildcard string. Even in the first case the trailing ".* is redundant, since what follows the "server" string is irrelevant.

来源：https://stackoverflow.com/questions/24493065/python-error-os-walk-ioerror

标签

python

file-io

filepath