PHP Simple way to replace or remove empty lines with str_replace

问题

$line-out = str_replace('\r', '', str_replace('\n', '', $line-in));

The above works for me but, I saw a [\n\r] example somewhere and I cannot seem to find it.

I just want to get rid any blank lines. The above is in a foreach loop.

Thanks for teaching.

回答1:

You shouldn't use - in variable names ;)

$line_out = preg_replace('/[\n\r]+/', '', $line_in);
$line_out = str_replace(array("\n", "\r"), '', $line_in);

Manual entries:

• http://php.net/manual/en/function.preg-replace.php
• http://php.net/manual/en/function.str-replace.php

回答2:

str_replace can be passed an array as:

$line_out = str_replace(array("\r","\n"), '', $line_in);

回答3:

This is from php.net's example #2 in str_replace (modified to suit the "environment"):

<?php
// Order of replacement
$str     = "Line 1\nLine 2\rLine 3\r\nLine 4\n";
$order   = array("\r\n", "\n", "\r");

// Processes \r\n's first so they aren't converted twice.
$newstr = str_replace($order, '', $str);

来源：https://stackoverflow.com/questions/3779464/php-simple-way-to-replace-or-remove-empty-lines-with-str-replace