问题
This is supposed to be a string class with a bunch of operators and functions, including two friend functions. And those two cause some trouble for me, because the compiler says that they can not access the private members. Here is my string.h:
#include <iostream>
#ifndef STR_H
#define STR_H
namespace MyStr
{
class Str
{
private:
unsigned int length;
char *data;
public:
Str();
Str(const Str&);
Str(const char*);
Str(char c, unsigned int db);
~Str();
char* cStr() const;
unsigned int getLength() const;
lots of irrevelant functions here...
friend int operator/ (const Str&, char);
friend std::ostream& operator<< (std::ostream&, const Str&);
};
}
#endif /* STR_H */
here is the main.cpp:
#include <iostream>
#include "Str.h"
using namespace std;
using namespace MyStr;
ostream& operator<< (ostream& out,const Str& str)
{
for (int i=0; i<str.length; i++)
{
out<<str.data[i];
}
out<<endl;
return out;
}
int operator/ (const Str& str, char c)
{
for (int i=0; i<str.length; i++)
{
if(str.data[i]==c) return i;
}
return -1;
}
This code won't compile, the compiler claiming that the Str
members are private.
回答1:
You should pay more attention to namespaces.
class Str {
private:
unsigned int length;
char *data;
public:
Str(){}
Str(const Str&){}
Str(const char*){}
Str(char c, unsigned int db){}
// maybe something more...
friend int operator/ (const Str&, char);
friend std::ostream& operator<< (std::ostream&, const Str&);
};
ostream& operator<< (ostream& out,const Str& str)
{
for (int i=0; i<str.length; i++)
out<<str.data[i];
out<<endl;
return out;
}
int operator/ (const Str& str, char c)
{
for (int i=0; i<str.length; i++)
if(str.data[i]==c) return i;
return -1;
}
int main()
{
Str s;
cout<<s;
return 0;
}
You get error because of the unmatched namespaces. If you prefer to stick with MyStr
then you should add namespace MyStr
to overloaded friend operators. This is how you can do it: (operators should be defined within namespace MyStr
)
namespace MyStr {
ostream& operator<< (ostream& out,const Str& str)
{
for (int i=0; i<str.length; i++)
{
out<<str.data[i];
}
out<<endl;
return out;
}
int operator/ (const Str& str, char c)
{
for (int i=0; i<str.length; i++)
{
if(str.data[i]==c) return i;
}
return -1;
}
}
回答2:
When you declare the friend functions inside Str
they are considered to be in the immediately enclosing namespace, MyStr
.
The operators you define are in the global namespace, so the compiler believes that those are two entirely different operators, and not the friends.
You can solve this by adding
namespace MyStr
{
}
around the operators in the .cpp file.
来源:https://stackoverflow.com/questions/15731414/c-friend-function-cant-access-private-members