问题
I am trying to aggregate a batch of documents. There are two fields in the documents I would like to $push. However, lets say they are "_id" and "A" fields, I only want $push "_id" and "A" if "A" is $gt 0.
I tried two approaches.
First one.
db.collection.aggregate([{
"$group":{
"field": {
"$push": {
"$cond":[
{"$gt":["$A", 0]},
{"id": "$_id", "A":"$A"},
null
]
}
},
"secondField":{"$push":"$B"}
}])
But this will push a null value to "field" and I don't want it.
Second one.
db.collection.aggregate([{
"$group":
"field": {
"$cond":[
{"$gt",["$A", 0]},
{"$push": {"id":"$_id", "A":"$A"}},
null
]
},
"secondField":{"$push":"$B"}
}])
The second one simply doesn't work...
Is there a way to skip the $push in else case?
ADDED:
Expected documents:
{
"_id":objectid(1),
"A":2,
"B":"One"
},
{
"_id":objectid(2),
"A":3,
"B":"Two"
},
{
"_id":objectid(3),
"B":"Three"
}
Expected Output:
{
"field":[
{
"A":"2",
"_id":objectid(1)
},
{
"A":"3",
"_id":objectid(2)
},
],
"secondField":["One", "Two", "Three"]
}
回答1:
This is my answer to the question after reading the post suggested by @Veeram
db.collection.aggregate([{
"$group":{
"field": {
"$push": {
"$cond":[
{"$gt":["$A", 0]},
{"id": "$_id", "A":"$A"},
null
]
}
},
"secondField":{"$push":"$B"}
},
{
"$project": {
"A":{"$setDifference":["$A", [null]]},
"B":"$B"
}
}])
回答2:
One more option is to use $filter operator:
db.collection.aggregate([
{
$group : {
_id: null,
field: { $push: { id: "$_id", A : "$A"}},
secondField:{ $push: "$B" }
}
},
{
$project: {
field: {
$filter: {
input: "$field",
as: "item",
cond: { $gt: [ "$$item.A", 0 ] }
}
},
secondField: "$secondField"
}
}])
On first step you combine your array and filter them on second step
来源:https://stackoverflow.com/questions/49687020/mongodb-aggregation-push-if-conditional