问题
I have a list of numbers which looks like this: 1.234D+1
or 1.234D-02
. I want to read the file using C. The function atof
will merely ignore the D
and translate only the mantissa.
The function fscanf
will not accept the format '%10.6e'
because it expects an E
instead of a D
in the exponent.
When I ran into this problem in Python, I gave up and merely used a string substitution before converting from string to float. But in C, I am sure there must be another way.
So, how would you read a file with numbers using D
instead of E
for scientific notation? Notice that I do not mean how to read the strings themselves, but rather how to convert them to floats.
Thanks.
回答1:
You can take advantage of strtod and strtok:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(void) {
char in[] = "1.234D+1 ABCD 1.234D-02 5\n";
char *cursor;
char *endp;
for ( cursor = strtok(in, " "); cursor; cursor = strtok(NULL, " ")) {
double d = strtod(cursor, &endp);
if ( *endp == 'D' ) {
*endp = 'e';
d = strtod(cursor, &endp);
}
if ( endp != cursor ) {
printf("%e\n", d);
}
}
return 0;
}
Output:
E:\> cnv 1.234000e+001 1.234000e-002 5.000000e+000
回答2:
replace D with E, by looping along string. then atof
.
回答3:
Here this function is to replace "D" into "E" in the scientific notation with "D".
std::string dToE(string cppstr)
{
str1.replace(cppstr.find("D"),1,"E");
return cppstr;
}
If the C string for scientific notation is defined by:
char * cstr = "1.2D+03";
or usually obtained by strtok
method, which returns C string, then use atof(dToE(string(cstr)).c_str())
to get the scientific notation with "E".
Since atof
only accept C style string, you should use c_str()
string method to convert C++ string into C string.
来源:https://stackoverflow.com/questions/2555097/reading-ascii-numbers-using-d-instead-of-e-for-scientific-notation-using-c