整理oracle 树形查询

sql树形递归查询是数据库查询的一种特殊情形，也是组织结构、行政区划查询的一种最常用的的情形之一。下面对该种查询进行一些总结：

create table JD2_SUPERVISE_MATTER
(
  id                     NUMBER(10) not null,
  pid                    NUMBER(10),
  data_model_id          NUMBER(10),
  code                   VARCHAR2(30),
  name                   VARCHAR2(30),
  descript               VARCHAR2(50),
  flag_notic_budget_unit CHAR(1),
  flag_notic_busi_dept   CHAR(1),
  busi_dept_name         VARCHAR2(30),
  orderid                NUMBER(10)
)

alter table JD2_SUPERVISE_MATTER
  add constraint PK_JD2_SUPERVISE_MATTER primary key (ID)

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (542, 362, null, 'ZCJH', '支出计划', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (543, 542, null, 'YKJH', '用款计划申请', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (544, 542, null, 'YKJHHZ', '用款计划汇总审核', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (481, 382, 361, 'ZJZFSP', '直接支付申请汇总审批', null, '0', '1', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (361, null, 302, 'YSBZ', '预算编制', null, '1', '0', '', null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (363, 361, 21, 'NCYS', '年初预算', null, '1', '1', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (362, null, 101, 'YSZX', '预算执行', null, '0', '1', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (381, 362, 61, 'SRZX', '收入执行', null, '0', '1', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (382, 362, 101, 'ZCZX', '支出执行', null, '0', '0', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (383, 382, null, 'ZFSP', '支付审批', null, '1', '0', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (384, 383, 281, 'ZJZF', '直接支付', null, '0', '1', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (521, null, 221, 'YSJH', '预算计划', null, '0', '1', null, null);

1、查找某个节点下面子孙节点

select * from JD2_SUPERVISE_MATTER start with id=361 connect by prior id=pid

2、查找节点的祖先节点

select * from JD2_SUPERVISE_MATTER start with id=361 connect by prior pid=id

在树形结构节点很多的情况一下，一般会采用异步刷新的方式进行，在默认加载的情况下，会展开到某个层级。这种情况下，不但要获取某个节点的祖先节点，还需要获取祖先节点的兄弟节点，在这种情况下可以通过level进行

select id,pid,level from JD2_SUPERVISE_MATTER where level>1
connect by prior id=pid start with id=361      order by level

显示出树的级别查询

select id,rpad(' ',(level-1)*4)||name,code,level from JD2_SUPERVISE_MATTER
 connect by pid = prior id   start with pid is null;

来源：https://www.cnblogs.com/ios9/p/9335954.html

标签

oracle执行计划

Oracle

oracle数据库