问题
I'm using ViewFLipper with Random.nextInt(). to change layouts onClick (Button). Now I have 3 xml layouts. 1_view.xml 2_view.xml 3_view.xml. Starting from 1_view.xml I have a button there. When button clicked I should get a random layout. it works. But the problem is now, sometimes I get the same layout (1_view.xml). When a user clicks a button on (1_view.xml), I want them to go to the layouts I have left (2_view.xml and 3_view.xml).
Codes
Main.xml
<RelativeLayout
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:padding="10dip" >
<TextView
android:id="@+id/TVLeft"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerVertical="true"
android:layout_gravity="left|top"
android:text="0"
android:textColor="#4CB848"
android:textSize="40sp"
android:textStyle="bold" />
<TextView
android:id="@+id/TVRight"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentRight="true"
android:layout_centerVertical="true"
android:layout_toRightOf="@+id/TVLeft"
android:gravity="right"
android:text="0"
android:textColor="#FF0000"
android:textSize="40sp"
android:textStyle="bold" />
</RelativeLayout>
<ViewFlipper
android:id="@+id/viewFlipper1"
android:layout_width="match_parent"
android:layout_height="wrap_content" >
<include
android:id="@+id/1_View"
layout="@layout/1_view" />
<include
android:id="@+id/2_View"
layout="@layout/2_view" />
<include
android:id="@+id/3_View"
layout="@layout/3_view" />
</ViewFlipper>
</LinearLayout>
Main.java
// FlipperView
MyViewFlipper = (ViewFlipper) findViewById(R.id.viewFlipper1);
TVRight = (TextView) findViewById(R.id.TVRight);
TVLeft = (TextView) findViewById(R.id.TVLeft);
// 1_view.xml
Q1_btn1 = (Button) findViewById(R.id.btn_1);
Q1_btn2 = (Button) findViewById(R.id.btn_2);
Q1_btn3 = (Button) findViewById(R.id.btn_3);
Q1_btn4 = (Button) findViewById(R.id.btn_4);
Q1_btn1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Wrongnum++;
WrongResult.setText(Integer.toString(Wrongnum));
}
});
Q1_btn2.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Rightnum++;
RightResult.setText(Integer.toString(Rightnum));
Random RandomView = new Random();
MyViewFlipper.setDisplayedChild(RandomView.nextInt(3));
}
});
Q1_btn3.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Wrongnum++;
WrongResult.setText(Integer.toString(Wrongnum));
}
});
Q1_btn4.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Wrongnum++;
WrongResult.setText(Integer.toString(Wrongnum));
}
});
回答1:
You can do this in your code:
Random RandomView = new Random();
int nextViewIndex = RandomView.nextInt(3);
while (nextViewIndex == MyViewFlipper.getDisplayedChild()) {
nextViewIndex = RandomView.nextInt(3);
}
MyViewFlipper.setDisplayedChild(nextViewIndex);
Basically just call Random.nextInt() until it doesn't match current viewFlipper's index.
To only show a viewFlipper once randomly:
// Intialize this once
List<Integer> vfIndices = new ArrayList<Integer>();
for (int i = 0; i < MyViewFlipper.getChildCount(); i++) {
vfIndices.add(i);
}
// when button is clicked
if (vfIndices.size() == 0) {
return; // no more view flipper to show!
}
int viewIndex = RandomView.nextInt(vfIndices.size());
MyViewFlipper.setDisplayedChild(vfIndices.get(viewIndex));
vfIndicies.remove(viewIndex);
The idea is use an ArrayList to keep track of the viewFlipper index that has not been shown. When button is clicked, pick an index randomly from this array and set the viewFlipper to. Then remove that index from the ArrayList. Next time the button is clicked, it will show one of the remaining flippers.
来源:https://stackoverflow.com/questions/11442287/using-viewflipper-with-onclick-to-switch-views