问题
I need a really, really fast method of checking if a string is JSON or not. I feel like this is not the best way:
function isJson($string) {
return ((is_string($string) &&
(is_object(json_decode($string)) ||
is_array(json_decode($string))))) ? true : false;
}
Any performance enthusiasts out there want to improve this method?
回答1:
function isJson($string) {
json_decode($string);
return (json_last_error() == JSON_ERROR_NONE);
}
回答2:
Answer to the Question
The function json_last_error returns the last error occurred during the JSON encoding and decoding. So the fastest way to check the valid JSON is
// decode the JSON data
// set second parameter boolean TRUE for associative array output.
$result = json_decode($json);
if (json_last_error() === JSON_ERROR_NONE) {
// JSON is valid
}
// OR this is equivalent
if (json_last_error() === 0) {
// JSON is valid
}
Note that json_last_error is supported in PHP >= 5.3.0 only.
Full program to check the exact ERROR
It is always good to know the exact error during the development time. Here is full program to check the exact error based on PHP docs.
function json_validate($string)
{
// decode the JSON data
$result = json_decode($string);
// switch and check possible JSON errors
switch (json_last_error()) {
case JSON_ERROR_NONE:
$error = ''; // JSON is valid // No error has occurred
break;
case JSON_ERROR_DEPTH:
$error = 'The maximum stack depth has been exceeded.';
break;
case JSON_ERROR_STATE_MISMATCH:
$error = 'Invalid or malformed JSON.';
break;
case JSON_ERROR_CTRL_CHAR:
$error = 'Control character error, possibly incorrectly encoded.';
break;
case JSON_ERROR_SYNTAX:
$error = 'Syntax error, malformed JSON.';
break;
// PHP >= 5.3.3
case JSON_ERROR_UTF8:
$error = 'Malformed UTF-8 characters, possibly incorrectly encoded.';
break;
// PHP >= 5.5.0
case JSON_ERROR_RECURSION:
$error = 'One or more recursive references in the value to be encoded.';
break;
// PHP >= 5.5.0
case JSON_ERROR_INF_OR_NAN:
$error = 'One or more NAN or INF values in the value to be encoded.';
break;
case JSON_ERROR_UNSUPPORTED_TYPE:
$error = 'A value of a type that cannot be encoded was given.';
break;
default:
$error = 'Unknown JSON error occured.';
break;
}
if ($error !== '') {
// throw the Exception or exit // or whatever :)
exit($error);
}
// everything is OK
return $result;
}
Testing with Valid JSON INPUT
$json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
$output = json_validate($json);
print_r($output);
Valid OUTPUT
Array
(
[0] => stdClass Object
(
[user_id] => 13
[username] => stack
)
[1] => stdClass Object
(
[user_id] => 14
[username] => over
)
)
Testing with invalid JSON
$json = '{background-color:yellow;color:#000;padding:10px;width:650px;}';
$output = json_validate($json);
print_r($output);
Invalid OUTPUT
Syntax error, malformed JSON.
Extra note for (PHP >= 5.2 && PHP < 5.3.0)
Since json_last_error is not supported in PHP 5.2, you can check if the encoding or decoding returns boolean FALSE. Here is an example
// decode the JSON data
$result = json_decode($json);
if ($result === FALSE) {
// JSON is invalid
}
Hope this is helpful. Happy Coding!
回答3:
All you really need to do is this...
if (is_object(json_decode($MyJSONArray)))
{
... do something ...
}
This request does not require a separate function even. Just wrap is_object around json_decode and move on. Seems this solution has people putting way too much thought into it.
回答4:
Using json_decode to "probe" it might not actually be the fastest way. If it's a deeply nested structure, then instantiating a lot of objects of arrays to just throw them away is a waste of memory and time.
So it might be faster to use preg_match and the RFC4627 regex to also ensure validity:
// in JS:
var my_JSON_object = !(/[^,:{}\[\]0-9.\-+Eaeflnr-u \n\r\t]/.test(
text.replace(/"(\\.|[^"\\])*"/g, '')));
The same in PHP:
return !preg_match('/[^,:{}\\[\\]0-9.\\-+Eaeflnr-u \\n\\r\\t]/',
preg_replace('/"(\\.|[^"\\\\])*"/', '', $json_string));
Not enough of a performance enthusiast to bother with benchmarks here however.
回答5:
This will return true if your string represents a json array or object:
function isJson($str) {
$json = json_decode($str);
return $json && $str != $json;
}
It rejects json strings that only contains a number, string or boolean, although those strings are technically valid json.
var_dump(isJson('{"a":5}')); // bool(true)
var_dump(isJson('[1,2,3]')); // bool(true)
var_dump(isJson('1')); // bool(false)
var_dump(isJson('1.5')); // bool(false)
var_dump(isJson('true')); // bool(false)
var_dump(isJson('false')); // bool(false)
var_dump(isJson('null')); // bool(false)
var_dump(isJson('hello')); // bool(false)
var_dump(isJson('')); // bool(false)
It is the shortest way I can come up with.
回答6:
The simplest and fastest way that I use is following;
$json_array = json_decode( $raw_json , true );
if( $json_array == NULL ) //check if it was invalid json string
die ('Invalid'); // Invalid JSON error
// you can execute some else condition over here in case of valid JSON
It is because json_decode() returns NULL if the entered string is not json or invalid json.
Simple function to validate JSON
If you have to validate your JSON in multiple places, you can always use the following function.
function is_valid_json( $raw_json ){
return ( json_decode( $raw_json , true ) == NULL ) ? false : true ; // Yes! thats it.
}
In the above function, you will get true in return if it is a valid JSON.
回答7:
function is_json($str){
return json_decode($str) != null;
}
http://tr.php.net/manual/en/function.json-decode.php return value is null when invalid encoding detected.
回答8:
You must validate your input to make sure the string you pass is not empty and is, in fact, a string. An empty string is not valid JSON.
function is_json($string) {
return !empty($string) && is_string($string) && is_array(json_decode($string, true)) && json_last_error() == 0;
}
I think in PHP it's more important to determine if the JSON object even has data, because to use the data you will need to call json_encode() or json_decode(). I suggest denying empty JSON objects so you aren't unnecessarily running encodes and decodes on empty data.
function has_json_data($string) {
$array = json_decode($string, true);
return !empty($string) && is_string($string) && is_array($array) && !empty($array) && json_last_error() == 0;
}
回答9:
Easy method is to check the json result..
$result = @json_decode($json,true);
if (is_array($result)) {
echo 'JSON is valid';
}else{
echo 'JSON is not valid';
}
回答10:
This will do it:
function isJson($string) {
$decoded = json_decode($string); // decode our JSON string
if ( !is_object($decoded) && !is_array($decoded) ) {
/*
If our string doesn't produce an object or array
it's invalid, so we should return false
*/
return false;
}
/*
If the following line resolves to true, then there was
no error and our JSON is valid, so we return true.
Otherwise it isn't, so we return false.
*/
return (json_last_error() == JSON_ERROR_NONE);
}
if ( isJson($someJsonString) ) {
echo "valid JSON";
} else {
echo "not valid JSON";
}
As shown in other answers, json_last_error() returns any error from our last json_decode(). However there are some edge use cases where this function alone is not comprehensive enough. For example, if you json_decode() an integer (eg: 123), or a string of numbers with no spaces or other characters (eg: "123"), the json_last_error() function will not catch an error.
To combat this, I've added an extra step that ensures the result of our json_decode() is either an object or an array. If it's not, then we return false.
To see this in action, check these two examples:
- Only check with json_last_error()
- Checking for object/array first
回答11:
in GuzzleHttp:
/**
* Wrapper for json_decode that throws when an error occurs.
*
* @param string $json JSON data to parse
* @param bool $assoc When true, returned objects will be converted
* into associative arrays.
* @param int $depth User specified recursion depth.
* @param int $options Bitmask of JSON decode options.
*
* @return mixed
* @throws \InvalidArgumentException if the JSON cannot be decoded.
* @link http://www.php.net/manual/en/function.json-decode.php
*/
function json_decode($json, $assoc = false, $depth = 512, $options = 0)
{
$data = \json_decode($json, $assoc, $depth, $options);
if (JSON_ERROR_NONE !== json_last_error()) {
throw new \InvalidArgumentException(
'json_decode error: ' . json_last_error_msg());
}
return $data;
}
/**
* Wrapper for JSON encoding that throws when an error occurs.
*
* @param mixed $value The value being encoded
* @param int $options JSON encode option bitmask
* @param int $depth Set the maximum depth. Must be greater than zero.
*
* @return string
* @throws \InvalidArgumentException if the JSON cannot be encoded.
* @link http://www.php.net/manual/en/function.json-encode.php
*/
function json_encode($value, $options = 0, $depth = 512)
{
$json = \json_encode($value, $options, $depth);
if (JSON_ERROR_NONE !== json_last_error()) {
throw new \InvalidArgumentException(
'json_encode error: ' . json_last_error_msg());
}
return $json;
}
回答12:
Earlier i was just checking for a null value, which was wrong actually.
$data = "ahad";
$r_data = json_decode($data);
if($r_data){//json_decode will return null, which is the behavior we expect
//success
}
The above piece of code works fine with strings. However as soon as i provide number, it breaks up.for example.
$data = "1213145";
$r_data = json_decode($data);
if($r_data){//json_decode will return 1213145, which is the behavior we don't expect
//success
}
To fix it what i did was very simple.
$data = "ahad";
$r_data = json_decode($data);
if(($r_data != $data) && $r_data)
print "Json success";
else
print "Json error";
回答13:
Another simple way
function is_json($str)
{
return is_array(json_decode($str,true));
}
回答14:
We need to check if passed string is not numeric because in this case json_decode raises no error.
function isJson($str) {
$result = false;
if (!preg_match("/^\d+$/", trim($str))) {
json_decode($str);
$result = (json_last_error() == JSON_ERROR_NONE);
}
return $result;
}
回答15:
I've tried some of those solution but nothing was working for me. I try this simple thing :
$isJson = json_decode($myJSON);
if ($isJson instanceof \stdClass || is_array($isJson)) {
echo("it's JSON confirmed");
} else {
echo("nope");
}
I think it's a fine solutiuon since JSON decode without the second parameter give an object.
EDIT : If you know what will be the input, you can adapt this code to your needs. In my case I know I have a Json wich begin by "{", so i don't need to check if it's an array.
回答16:
I don't know about performance or elegance of my solution, but it's what I'm using:
if (preg_match('/^[\[\{]\"/', $string)) {
$aJson = json_decode($string, true);
if (!is_null($aJson)) {
... do stuff here ...
}
}
Since all my JSON encoded strings start with {" it suffices to test for this with a RegEx. I'm not at all fluent with RegEx, so there might be a better way to do this. Also: strpos() might be quicker.
Just trying to give in my tuppence worth.
P.S. Just updated the RegEx string to /^[\[\{]\"/ to also find JSON array strings. So it now looks for either [" or {" at the beginning of the string.
回答17:
Expanding on this answer How about the following:
<?php
$json = '[{"user_id":13,"username":"stack"},{"user_id":14,"username":"over"}]';
//$json = '12';
function isJson($string) {
json_decode($string);
if(json_last_error() == JSON_ERROR_NONE) {
if(substr($string,0,1) == '[' && substr($string,-1) == ']') { return TRUE; }
else if(substr($string,0,1) == '{' && substr($string,-1) == '}') { return TRUE; }
else { return FALSE; }
}
}
echo isJson($json);
?>
回答18:
Should be something like this:
function isJson($string)
{
// 1. Speed up the checking & prevent exception throw when non string is passed
if (is_numeric($string) ||
!is_string($string) ||
!$string) {
return false;
}
$cleaned_str = trim($string);
if (!$cleaned_str || !in_array($cleaned_str[0], ['{', '['])) {
return false;
}
// 2. Actual checking
$str = json_decode($string);
return (json_last_error() == JSON_ERROR_NONE) && $str && $str != $string;
}
UnitTest
public function testIsJson()
{
$non_json_values = [
"12",
0,
1,
12,
-1,
'',
null,
0.1,
'.',
"''",
true,
false,
[],
'""',
'[]',
' {',
' [',
];
$json_values = [
'{}',
'{"foo": "bar"}',
'[{}]',
' {}',
' {} '
];
foreach ($non_json_values as $non_json_value) {
$is_json = isJson($non_json_value);
$this->assertFalse($is_json);
}
foreach ($json_values as $json_value) {
$is_json = isJson($json_value);
$this->assertTrue($is_json);
}
}
回答19:
Hi here's a little snippet from my library, in this first condition I'm just checking if the data is json then return it if correctly decoded, please note the substr usage for performance ( I haven't seen yet any json file not begining neither by { or [
$input=trim($input);
if ((substr($input, 0, 1) == '{' && substr($input, -1) == '}') or (substr($input, 0, 1) == '[' && substr($input, -1) == ']')) {
$output = json_decode($input, 1);
if (in_array(gettype($output),['object','array'])) {
#then it's definitely JSON
}
}
回答20:
The custom function
function custom_json_decode(&$contents=NULL, $normalize_contents=true, $force_array=true){
//---------------decode contents---------------------
$decoded_contents=NULL;
if(is_string($contents)){
$decoded_contents=json_decode($contents,$force_array);
}
//---------------normalize contents---------------------
if($normalize_contents===true){
if(is_string($decoded_contents)){
if($decoded_contents==='NULL'||$decoded_contents==='null'){
$contents=NULL;
}
elseif($decoded_contents==='FALSE'||$decoded_contents==='false'){
$contents=false;
}
}
elseif(!is_null($decoded_contents)){
$contents=$decoded_contents;
}
}
else{
//---------------validation contents---------------------
$contents=$decoded_contents;
}
return $contents;
}
Cases
$none_json_str='hello';
//------------decoding a none json str---------------
$contents=custom_json_decode($none_json_str); // returns 'hello'
//------------checking a none json str---------------
custom_json_decode($none_json_str,false);
$valid_json=false;
if(!is_null($none_json_str)){
$valid_json=true;
}
Resources
https://gist.github.com/rafasashi/93d06bae83cc1a1f440b
回答21:
Freshly-made function for PHP 5.2 compatibility, if you need the decoded data on success:
function try_json_decode( $json, & $success = null ){
// non-strings may cause warnings
if( !is_string( $json )){
$success = false;
return $json;
}
$data = json_decode( $json );
// output arg
$success =
// non-null data: success!
$data !== null ||
// null data from 'null' json: success!
$json === 'null' ||
// null data from ' null ' json padded with whitespaces: success!
preg_match('/^\s*null\s*$/', $json );
// return decoded or original data
return $success ? $data : $json;
}
Usage:
$json_or_not = ...;
$data = try_json_decode( $json_or_not, $success );
if( $success )
process_data( $data );
else what_the_hell_is_it( $data );
Some tests:
var_dump( try_json_decode( array(), $success ), $success );
// ret = array(0){}, $success == bool(false)
var_dump( try_json_decode( 123, $success ), $success );
// ret = int(123), $success == bool(false)
var_dump( try_json_decode(' ', $success ), $success );
// ret = string(6) " ", $success == bool(false)
var_dump( try_json_decode( null, $success ), $success );
// ret = NULL, $success == bool(false)
var_dump( try_json_decode('null', $success ), $success );
// ret = NULL, $success == bool(true)
var_dump( try_json_decode(' null ', $success ), $success );
// ret = NULL, $success == bool(true)
var_dump( try_json_decode(' true ', $success ), $success );
// ret = bool(true), $success == bool(true)
var_dump( try_json_decode(' "hello" ', $success ), $success );
// ret = string(5) "hello", $success == bool(true)
var_dump( try_json_decode(' {"a":123} ', $success ), $success );
// ret = object(stdClass)#2 (1) { ["a"]=> int(123) }, $success == bool(true)
回答22:
function is_json($input) {
$input = trim($input);
if (substr($input,0,1)!='{' OR substr($input,-1,1)!='}')
return false;
return is_array(@json_decode($input, true));
}
回答23:
A simple modification to henrik's answer to touch most required possibilities.
( including " {} and [] " )
function isValidJson($string) {
json_decode($string);
if(json_last_error() == JSON_ERROR_NONE) {
if( $string[0] == "{" || $string[0] == "[" ) {
$first = $string [0];
if( substr($string, -1) == "}" || substr($string, -1) == "]" ) {
$last = substr($string, -1);
if($first == "{" && $last == "}"){
return true;
}
if($first == "[" && $last == "]"){
return true;
}
return false;
}
return false;
}
return false;
}
return false;
}
回答24:
The fastest way to maybe decode a possible JSON object to a PHP object/array:
/**
* If $value is a JSON encoded object or array it will be decoded
* and returned.
* If $value is not JSON format, then it will be returned unmodified.
*/
function get_data( $value ) {
if ( ! is_string( $value ) ) { return $value; }
if ( strlen( $value ) < 2 ) { return $value; }
if ( '{' != $value[0] && '[' != $value[0] ) { return $value; }
$json_data = json_decode( $value );
if ( ! $json_data ) { return $value; }
return $json_data;
}
回答25:
Another suggestion from me :)
function isJson(string $string) {
return ($result = json_decode($string, true)) ? $result : $string;
}
来源：https://stackoverflow.com/questions/6041741/fastest-way-to-check-if-a-string-is-json-in-php