问题
I have my code that will read in a a list of numbers in a file called "QuizScores.txt". However, in this file, certain numbers contain letters. I have told my program to simply ignore those instances and move onto the next number. My issue now if that my code is only reading one line at a time where I need it to look at the entire file, read it in, calculate the average, the maximum, and the minimum, and finally output that to a file called "QuizStats.txt". Any help with this would be greatly appreciated! Thanks!
QuizScores:
45
63
74g
34.7
75
4
8
15
16
23
42
67f
34
67
Code:
import java.io.*;
public class ScoreReader {
public static void main(String[] args) {
BufferedReader reader = null;
try {
String currentLine;
reader = new BufferedReader(new FileReader("QuizScores.txt"));
while ((currentLine = reader.readLine()) != null) {
int sum = 0;
String[] nums = currentLine.split("\\s+");
for (int i = 0; i < nums.length; i++) {
try{
double num = Integer.parseInt(nums[i]);
if (num != -1) {
sum += num;
}
} catch( NumberFormatException err )
{
}
}
System.out.println(sum);
}
} catch (IOException err) {
err.printStackTrace();
}
catch (NumberFormatException err) {}
finally {
try {
if (reader != null){
reader.close();
}
}
catch (IOException err) {
err.printStackTrace();
}
}
}
}
回答1:
Try this code
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ScoreReader {
public static void main(String[] args) {
BufferedReader reader = null;
double average = 200.0;
double min = Double.MAX_VALUE;
double max = Double.MIN_VALUE;
int n = 1;
String currentLine;
double c;
try {
reader = new BufferedReader(new FileReader("QuizScores.txt"));
System.out.println("--Quiz Scores--");
while ((currentLine = reader.readLine()) != null) {
try {
c = Double.parseDouble(currentLine);
} catch (Exception ex) {
continue;
}
max = max > c ? max : c;
min = min < c ? min : c;
average += (c - average) / n;
n++;
System.out.println(c);
}
System.out.println("--Summary--");
System.out.println("Average: " + average);
System.out.println("Minimum: " + min);
System.out.println("Maximum: " + max);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output
--Quiz Scores--
45.0
63.0
34.7
75.0
4.0
8.0
15.0
16.0
23.0
42.0
67.0
34.0
67.0
--Summary--
Average: 37.97692307692308
Minimum: 4.0
Maximum: 75.0
Is this what you are looking for?
回答2:
double min = 0.0;
double max = 0.0;
int count = 0;
sum += num;
count++;
if (num > max) {
max = num;
}
if (num < min) {
min = num;
}
double avg = (double) sum/count;
Then the avg, sum, min, and max are all known. I would probably take a different approach from the beginning, but the code above should work with your code. I have not run it though.
回答3:
Read line by line parsing only the numbers and put those into a list, then pass that list to a function such as:
public static Float getAverage(ArrayList <Float> x)
{
Float sum = 0.0f;
for (Float a : x )
sum += a;
return sum / x.size();
}
回答4:
private class Statistics{
public double min = -1;
public double max;
public double avg;
public long sum;
Statistics(List<Long> list){
int count = 0;
for (Long num : list) {
sum += num;
count++;
if(min == -1) min= num;
if (num > max) {
max = num;
}
if (num < min) {
min = num;
}
}
this.avg = sum/(double)count;
}
}
// USAGE
Statistics statistics = new Statistics(Arrays.asList(1l, 2l, 3l, 4l));
System.out.println(statistics.avg);
System.out.println(statistics.min);
System.out.println(statistics.max);
System.out.println(statistics.sum);
来源:https://stackoverflow.com/questions/22996974/calculating-average-max-min-from-an-array-in-java