Casperjs - trying to run casper script from command line doesn't output correctly

问题

I'm brand new to casperjs, and in the process of trying to run my first casper script from the command line (using $ casperjs sample.js), I received this output:

Casper CLI passed args:
[]
Casper CLI passed options:
{
    "casper-path": "/usr/local/Cellar/casperjs/1.1-beta2/libexec",
    "cli": true
}

Instead of the predicted output of:

CasperJS, a navigation scripting and testing utility for PhantomJS
PhantomJS: Headless WebKit with JavaScript API

Here are the contents of the sample file:

var casper = require('casper').create();

casper.start('http://casperjs.org/', function() {
    this.echo(this.getTitle());
});

casper.thenOpen('http://phantomjs.org', function() {
    this.echo(this.getTitle());
});

casper.run();

I installed casperjs using the latest version of homebrew.

Any help is much appreciated. Thanks in advance.

回答1:

It looks like you aren't running the sample that you think you are.

The output you gave came from this code:

var casper = require("casper").create();

casper.echo("Casper CLI passed args:");
require("utils").dump(casper.cli.args);

casper.echo("Casper CLI passed options:");
require("utils").dump(casper.cli.options);

casper.exit();

You could try running less sample.js to verify the contents of sample.js.

Source

来源：https://stackoverflow.com/questions/21125834/casperjs-trying-to-run-casper-script-from-command-line-doesnt-output-correctl