Pair IP addresses in a list pulled from xlrd

问题

I have used xlrd to pull data from a column (Data Below). I need to group together the ip addressess. So ip address that appear next together in the output belong to the same pool and single ones are in a pool of their own. For example (10.100.33.183,10.100.33.184) belong to (pool1). (Pool6 =10.100.33.89)

How do I go about achieving this all help welcome.

['', '', '', '', '', '', '', 'Pool Member IP', '', '10.100.33.184 (S56723FR6VL01)', '10.100.33.183 (S56723FR6VL02)', '', '', '', '', '', '', '', '10.101.33.182 (S56723FR6VL03)', '10.100.33.181 (S56723FR6VL04)', '', '', '', '', '', '', '', '10.100.33.180 (S56723FR6VL05)', '10.100.33.179 (S56723FR6VL06)', '', '', '', '', '', '', '', '10.100.33.178 (S56723FR6VL07)', '10.100.33.177 (S56723FR6VL08)', '', '', '', '', '', '', '', '10.100.33.90 (S56723FR6VL09)', '', '', '', '', '', '', '', '', '10.100.33.89 (S56723FR6VL0A)', '', '', '', '', '', '', '', '', '10.100.33.91 (S56723FR6VW01)', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']

回答1:

ip_data = ['', '', '', '', '', '', '', 'Pool Member IP', '', '10.100.33.184 (S56723FR6VL01)', '10.100.33.183 (S56723FR6VL02)', '', '', '', '', '', '', '', '10.101.33.182 (S56723FR6VL03)', '10.100.33.181 (S56723FR6VL04)', '', '', '', '', '', '', '', '10.100.33.180 (S56723FR6VL05)', '10.100.33.179 (S56723FR6VL06)', '', '', '', '', '', '', '', '10.100.33.178 (S56723FR6VL07)', '10.100.33.177 (S56723FR6VL08)', '', '', '', '', '', '', '', '10.100.33.90 (S56723FR6VL09)', '', '', '', '', '', '', '', '', '10.100.33.89 (S56723FR6VL0A)', '', '', '', '', '', '', '', '', '10.100.33.91 (S56723FR6VW01)', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
ip_pools = [[]]  # it starts as a list with an empty list at its last (and only) index
for ip_address in ip_data[ip_data.index('Pool Member IP')+1:]:
    if not ip_address:  # ip_address is ''
        if ip_pools[-1]:  # the last element of ip_pools is NOT an empty list: []
            ip_pools.append([])  # for the next ip pool
    else:  # ip_address is not empty
        # ip_pools[-1].append(ip_address)  # if you need the whole text
        ip_pools[-1].append(ip_address.partition(' ')[0])  # if you just want the number
if [] in ip_pools:
    ip_pools.remove([])  # to remove last empty list (if exists)

EDIT: Corrected the for sentence

回答2:

@franciscosollima's solution is good. Here's another way with regex.

iplist = ['', '', '', '', '', '', '', 'Pool Member IP', '', '10.100.33.184 (S56723FR6VL01)', '10.100.33.183 (S56723FR6VL02)', '', '', '', '', '', '', '', '10.101.33.182 (S56723FR6VL03)', '10.100.33.181 (S56723FR6VL04)', '', '', '', '', '', '', '', '10.100.33.180 (S56723FR6VL05)', '10.100.33.179 (S56723FR6VL06)', '', '', '', '', '', '', '', '10.100.33.178 (S56723FR6VL07)', '10.100.33.177 (S56723FR6VL08)', '', '', '', '', '', '', '', '10.100.33.90 (S56723FR6VL09)', '', '', '', '', '', '', '', '', '10.100.33.89 (S56723FR6VL0A)', '', '', '', '', '', '', '', '', '10.100.33.91 (S56723FR6VW01)', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']

import re

p = re.compile('[\d]+(?:\.[\d]+){3}')

pools = [[]]

for ip in iplist:
    m = p.match(ip)
    if m:
        pools[-1].append(m.group(0))
    elif not pools[-1]:
        continue
    else:
        pools.append([])

if [] in pools:
    pools.remove([])

for i, p in enumerate(pools, 1):
    print("Group " + str(i) +": " + str(p))

It's as simple as adding consecutive matches to the same pool. Otherwise, initialise a new one. The regex pattern will match from the start, and you may configure it detect IPv6 addresses too.

Prints out:

Group 1: ['10.100.33.184', '10.100.33.183']
Group 2: ['10.101.33.182', '10.100.33.181']
Group 3: ['10.100.33.180', '10.100.33.179']
Group 4: ['10.100.33.178', '10.100.33.177']
Group 5: ['10.100.33.90']
Group 6: ['10.100.33.89']
Group 7: ['10.100.33.91']

回答3:

ips = [ip.split()[0] for ip in data if ip[0].isdigit()]
sort = sorted(ips, key= lambda ip: int(ip.split('.')[-1]))
i, l, c = 0, len(sort), 1
pools = {}
while i < l:
    if int(sort[i].split('.')[-1]) == int(sort[i+1]).split('.')[-1])-1:
        pools[c] = (sort[i], sort[i+1])
        i += 2
    else:
        pools[c] = (sort[i],)
        i += 1
    c += 1

回答4:

May i play a bit with itertools for an answer?

test = ['', '', '', '', '', '', '', 'Pool Member IP', '', '10.100.33.184 (S56723FR6VL01)', '10.100.33.183 (S56723FR6VL02)', '', '', '', '', '', '', '', '10.101.33.182 (S56723FR6VL03)', '10.100.33.181 (S56723FR6VL04)', '', '', '', '', '', '', '', '10.100.33.180 (S56723FR6VL05)', '10.100.33.179 (S56723FR6VL06)', '', '', '', '', '', '', '', '10.100.33.178 (S56723FR6VL07)', '10.100.33.177 (S56723FR6VL08)', '', '', '', '', '', '', '', '10.100.33.90 (S56723FR6VL09)', '', '', '', '', '', '', '', '', '10.100.33.89 (S56723FR6VL0A)', '', '', '', '', '', '', '', '', '10.100.33.91 (S56723FR6VW01)', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
import itertools
def isplit(iterable,splitters):
    return [list(g) for k,g in itertools.groupby(iterable,lambda x:x in splitters) if not k]
test.remove('Pool Member IP')
pool = 0
for list in isplit(test,''):
    if len(list):
        pool+=1
    print(pool, list)

Prints out:

1 ['10.100.33.184 (S56723FR6VL01)', '10.100.33.183 (S56723FR6VL02)']
2 ['10.101.33.182 (S56723FR6VL03)', '10.100.33.181 (S56723FR6VL04)']
3 ['10.100.33.180 (S56723FR6VL05)', '10.100.33.179 (S56723FR6VL06)']
4 ['10.100.33.178 (S56723FR6VL07)', '10.100.33.177 (S56723FR6VL08)']
5 ['10.100.33.90 (S56723FR6VL09)']
6 ['10.100.33.89 (S56723FR6VL0A)']
7 ['10.100.33.91 (S56723FR6VW01)']

Kudos to Split a list into nested lists on a value and google-fu

来源：https://stackoverflow.com/questions/44949643/pair-ip-addresses-in-a-list-pulled-from-xlrd

标签

python

list

keyvaluepair