问题
i have a problem. i don't really understand how should i output this correctly using loops.
Table Data:
| Name | Position |
|:-------------------|----------------:|
| MARK NICHOLS | Team Lead|
| NICHOLAS CRUZ | Team Lead|
| SEAN PARKER | Programmer|
| MICHAEL SHAW | Programmer|
| LAURA ALVAREZ | Junior|
| JOHN FLORES | Junior|
I want is in every 2 fetched data the ID and Parent Variable in json must be change like this.:
while loop of table from above(){
on this part this is the default value in first loop of 2 data
3.1
is a CHILD ID and3.2
3
is a PARENT ID and3
//1loop
3.1 3.2
3 3
dynamic loop after the first loop
//2loop
CHILD 3.1.1 3.2.1
PARENT 3.1 3.2
//3loop
CHILD 3.1.1.1 3.2.1.1
PARENT 3.1.1 3.2.1
//4loop
CHILD 3.1.1.1.1 3.2.1.1.1
PARENT 3.1.1.1 3.2.1.1
//and so on....
}
see the child ID of second loop has a value of 3.1.1
after that second loop the child ID of second loop must be use in 3rd loop as a parent ID
let say in every loop of child add .1
. and the parent is the last child loop.
Static Json:
{
"id": "3.1",
"text": "Team Lead",
"title": "MARK NICHOLS",
"img": "../common/img/avatar-10.png",
"parent": "3"
},
{
"id": "3.2",
"text": "Team Lead",
"title": "NICHOLAS CRUZ",
"img": "../common/img/avatar-10.png",
"parent": "3"
},
{
"id": "3.1.1",
"text": "Programmer",
"title": "SEAN PARKER",
"img": "../common/img/avatar-10.png",
"parent": "3.1"
},
{
"id": "3.2.1",
"text": "Programmer",
"title": "MICHAEL SHAW",
"img": "../common/img/avatar-8.png",
"parent": "3.2"
},{
"id": "3.1.1.1",
"text": "Junior",
"title": "LAURA ALVAREZ",
"img": "../common/img/avatar-10.png",
"parent": "3.1.1"
},
{
"id": "3.2.1.1",
"text": "Junior",
"title": "JOHN FLORES",
"img": "../common/img/avatar-8.png",
"parent": "3.2.1"
}
Chart Layout Result Of Static Json:
What if i use the Table Data Above And Select All Data Using SQL. this PHP code must be convert like the Static Json Above?
My Trial Code:
<?php
$count = 6;
$a = "3.";
$b = "3";
$c = 1;
$e = "";
$f = "";
echo "<pre>";
for ($i=1; $i <=$count; $i++){
if ($c == 1){
$d =1;
}
if ($c == 2){
$d = 2;
}
echo "{";
echo "ID:".$a.$c.$e.$f.",";
$parent = $a.$c.$e.$f;
echo "Parent:".$parent;
echo "}";
if($i == $count){
}
else{
echo ",";
}
if ($c == 2){
$c = 0;
$e =".1";
}
$f += $e;
$c++;
}
?>
Logical Error Result:
{ID:3.1,Parent:3.1},
{ID:3.20,Parent:3.20},
{ID:3.1.10.1,Parent:3.1.10.1},
{ID:3.2.10.2,Parent:3.2.10.2},
{ID:3.1.10.3,Parent:3.1.10.3},
{ID:3.2.10.4,Parent:3.2.10.4}
Expected output on my trial code:
{ID:3.1,Parent:3},
{ID:3.2,Parent:3},
{ID:3.1.1,Parent:3.1},
{ID:3.2.1,Parent:3.2},
{ID:3.1.1.1,Parent:3.1.1},
{ID:3.2.1.1,Parent:3.2.1}
Please Help Me, If Someone There Having A Great Knowledge On Json and PHP to output Dynamic dhtmlx chart using loop to Json. Other Method Will Be Accepted.
回答1:
function loop(array $parents, $need)
{
$children = [];
$isLast = $need === 1;
$lastKey = count($parents) - 1;
foreach ($parents as $key => $parent) {
$id = $parent === 3 ? $key + 1 : 1;
$children[] = $child = "$parent.$id";
$comma = $isLast && $key === $lastKey ? '' : ',';
echo "{ID:$child,Parent:$parent}$comma" . "<br/>";
}
$need--;
if ($need) {
return loop($children, $need);
}
return $children;
}
loop([3, 3], 4);
回答2:
i fix my problem here's my answer on my question:
SQL:
$sql = mysqli_query($conn,"SELECT * FROM `brgy_official_detail` bod
INNER JOIN resident_detail rd ON rd.res_ID = bod.res_ID
LEFT JOIN ref_suffixname rs ON rs.suffix_ID = rd.suffix_ID
LEFT JOIN ref_position rp ON rp.position_ID = bod.commitee_assignID
WHERE visibility = 1 AND position_Name LIKE 'Barangay Official%'");
count the query content:
$count_official = mysqli_num_rows($sql);
Declaring temp array:
$name = array();
$position_Name = array();
$official_img = array();
Fetch the data and save to array:
while($official_data = mysqli_fetch_array($sql)){
$suffix = $official_data['suffix'];
if ($suffix == "N/A") {
$suffix = "";
}
else{
$suffix = $official_data['suffix'];
}
$name[] = $official_data['res_fName'].' '.$official_data['res_mName'].' '.$official_data['res_lName'].' '.$suffix;
$position_Name[] = $official_data['position_Name'];
if (isset($official_data['res_Img'])) {
$z = $official_data['res_Img'];
$official_img[] = "data:image/jpeg;base64,".base64_encode($z);
}
else{
$official_img[] = "../../Img/Icon/logo.png";
}
}
and then i improve qskane answer:
function loop(array $parents, $need,$index,$name,$position_Name,$official_img)
{
$children = [];
$isLast = $need === 1;
$lastKey = count($parents) - 1;
foreach ($parents as $key => $parent) {
$p_name = $name[$index];
$pos_Name = $position_Name[$index];
$img = $official_img[$index];
$id = $parent === 3 ? $key + 1 : 1;
$children[] = $child = "$parent.$id";
$comma = $isLast && $key === $lastKey ? '' : ',';
echo "{
\"id\":\"$child\",
\"text\": \"$pos_Name\",
\"title\": \"$p_name\",
\"width\": 350,
\"img\": \"$img\",
\"parent\":\"$parent\"
}$comma";
}
$index++;
$need--;
if ($need) {
return loop($children, $need,$index,$name,$position_Name,$official_img);
}
return $children;
}
$index = 0;
loop([3], $count_official,$index,$name,$position_Name,$official_img);
?>
];
Result:
来源:https://stackoverflow.com/questions/50028788/dynamic-dhtmlx-organization-chart-using-php-and-json