问题
Hi to all the members of the community, I am trying to find out how to compare elements of my DB and identify them by a new binary variable. My DB is like this:
id=rep((1:2),5)
date<-seq(from=as.Date("2013-01-1"),to=as.Date("2013-01-05"),by=1)
trap<-c(1,1,3,1,4,2,3,4,1,4)
DB<-data.frame(id,date,trap)
DB<-DB[order(DB$date),]
DB$id[2]<-1
DB$trap[2]<-1
result<-c("N","N","N","N","N","N","Y","Y","Y","Y")
DB<-cbind(DB,result)
and I want to identify all the elements for which the id is different, but the date and trap value is the same, as report in the column result.
I have tried some codes (basically derived from another "similar" question) with the ave
function, but unsuccessfully.
As always any tips will be appreciate!!
回答1:
(duplicated(DB[,-1]) | duplicated(DB[,-1],fromLast=TRUE)) &
!(duplicated(DB) | duplicated(DB,fromLast=TRUE))
#[1] FALSE FALSE FALSE FALSE FALSE FALSE TRUE TRUE TRUE TRUE
回答2:
You could make a double loop over your data frame:
apply(DB, 1, function(r){
if(any(apply(DB, 1, function(x)(x[1]!= r[1] & all(x[c(2,3)]==r[c(2,3)])))))
"Y"
else
"N"
})
gives:
1 6 2 7 3 8 4 9 5 10
"N" "N" "N" "N" "N" "N" "Y" "Y" "Y" "Y"
来源:https://stackoverflow.com/questions/16563165/how-to-identify-similar-rows-in-r