问题
I'm trying to send a QStandardItemModel-derived object to PythonQt, but I'm a little confused on how it needs to be sent. When I was using boost::python I had several controls like boost::noncopyable to ensure I wasn't recreating this object, but sharing it with python. I also had constructs to provide a boost shared pointer to python from inside python.
class Scene : public boost::enable_shared_from_this<Scene>, public QStandardItemModel
In PythonQt, however, I'm not sure what's available. The function call
takes a QVariantList for all the function parameters.
QVariant PythonQt::call(PyObject* object, const QString &callable, const QVariantList &args = QVariantList))
What I'm confused about now is how to get my object to python via a QVariant. Since its derived from QStandardItemModel, I figured it would already be register
void MyObject::someFunction(QString fileName)
{
QVariant myObjectV = qVariantFromValue(this);
// send to python
...
}
But this gives me the following error:
'qt_metatype_id' : is not a member of 'QMetaTypeId<MyObject>'
I've tried registering it after I declare my class, but this throws a different error.
class MyObject : public QStandardItemModel
{
Q_OBJECT
...
};
Q_DECLARE_METATYPE(MyObject)
QStandardItemModel::QStandardItemModel(const QStandardItemModel&) is private within this context.
I actually get the error twice--once in header where I add the Q_DECLARE_METATYPE and in another header, which has a class which always derives from QStandardItemModel but is otherwise unrelated.
Is Q_DECLARE_METATYPE even the correct way to go about converting this object to a QVariant?
BOOST_PYTHON_MODULE(scene) { class_("Scene"); }
回答1:
Yes, by default, QVariant
can take one of te following types - http://doc.qt.io/qt-4.8/qvariant.html#Type-enum - and they are not enough for your task. You should declare additional types by yourself via qmetatype system. Thus you shoud call qRegisterMetaType() function.
来源:https://stackoverflow.com/questions/8279649/convert-a-qstandarditemmodel-to-a-qvariant