问题
Let\'s assume we have such a trivial daemon written in python:
def mainloop():
while True:
# 1. do
# 2. some
# 3. important
# 4. job
# 5. sleep
mainloop()
and we daemonize it using start-stop-daemon
which by default sends SIGTERM
(TERM
) signal on --stop
.
Let\'s suppose the current step performed is #2
. And at this very moment we\'re sending TERM
signal.
What happens is that the execution terminates immediately.
I\'ve found that I can handle the signal event using signal.signal(signal.SIGTERM, handler)
but the thing is that it still interrupts the current execution and passes the control to handler
.
So, my question is - is it possible to not interrupt the current execution but handle the TERM
signal in a separated thread (?) so that I was able to set shutdown_flag = True
so that mainloop()
had a chance to stop gracefully?
回答1:
A class based clean to use solution:
import signal
import time
class GracefulKiller:
kill_now = False
def __init__(self):
signal.signal(signal.SIGINT, self.exit_gracefully)
signal.signal(signal.SIGTERM, self.exit_gracefully)
def exit_gracefully(self,signum, frame):
self.kill_now = True
if __name__ == '__main__':
killer = GracefulKiller()
while not killer.kill_now:
time.sleep(1)
print("doing something in a loop ...")
print "End of the program. I was killed gracefully :)"
回答2:
Firstly I'm not certain that you need a second thread to set the shutdown_flag. Why not set it directly in the SIGTERM handler?
An alternative is to raise an exception from the SIGTERM
handler, which will be propagated up the stack. Assuming you've got proper exception handling (e.g. with with
/contextmanager
and try: ... finally:
blocks) this should be a fairly graceful shutdown, similar to if you were to Ctrl-C
your program.
Example program signals-test.py
:
#!/usr/bin/python
from time import sleep
import signal
import sys
def sigterm_handler(_signo, _stack_frame):
# Raises SystemExit(0):
sys.exit(0)
if sys.argv[1] == "handle_signal":
signal.signal(signal.SIGTERM, sigterm_handler)
try:
print "Hello"
i = 0
while True:
i += 1
print "Iteration #%i" % i
sleep(1)
finally:
print "Goodbye"
Now see the Ctrl-C behaviour:
$ ./signals-test.py default
Hello
Iteration #1
Iteration #2
Iteration #3
Iteration #4
^CGoodbye
Traceback (most recent call last):
File "./signals-test.py", line 21, in <module>
sleep(1)
KeyboardInterrupt
$ echo $?
1
This time I send it SIGTERM
after 4 iterations with kill $(ps aux | grep signals-test | awk '/python/ {print $2}')
:
$ ./signals-test.py default
Hello
Iteration #1
Iteration #2
Iteration #3
Iteration #4
Terminated
$ echo $?
143
This time I enable my custom SIGTERM
handler and send it SIGTERM
:
$ ./signals-test.py handle_signal
Hello
Iteration #1
Iteration #2
Iteration #3
Iteration #4
Goodbye
$ echo $?
0
回答3:
I think you are near to a possible solution.
Execute mainloop
in a separate thread and extend it with the property shutdown_flag
. The signal can be caught with signal.signal(signal.SIGTERM, handler)
in the main thread (not in a separate thread). The signal handler should set shutdown_flag
to True and wait for the thread to end with thread.join()
回答4:
Here is a simple example without threads or classes.
import signal
run = True
def handler_stop_signals(signum, frame):
global run
run = False
signal.signal(signal.SIGINT, handler_stop_signals)
signal.signal(signal.SIGTERM, handler_stop_signals)
while run:
pass # do stuff including other IO stuff
回答5:
Based on the previous answers, I have created a context manager which protects from sigint and sigterm.
import logging
import signal
import sys
class TerminateProtected:
""" Protect a piece of code from being killed by SIGINT or SIGTERM.
It can still be killed by a force kill.
Example:
with TerminateProtected():
run_func_1()
run_func_2()
Both functions will be executed even if a sigterm or sigkill has been received.
"""
killed = False
def _handler(self, signum, frame):
logging.error("Received SIGINT or SIGTERM! Finishing this block, then exiting.")
self.killed = True
def __enter__(self):
self.old_sigint = signal.signal(signal.SIGINT, self._handler)
self.old_sigterm = signal.signal(signal.SIGTERM, self._handler)
def __exit__(self, type, value, traceback):
if self.killed:
sys.exit(0)
signal.signal(signal.SIGINT, self.old_sigint)
signal.signal(signal.SIGTERM, self.old_sigterm)
if __name__ == '__main__':
print("Try pressing ctrl+c while the sleep is running!")
from time import sleep
with TerminateProtected():
sleep(10)
print("Finished anyway!")
print("This only prints if there was no sigint or sigterm")
回答6:
Found easiest way for me. Here an example with fork for clarity that this way is useful for flow control.
import signal
import time
import sys
import os
def handle_exit(sig, frame):
raise(SystemExit)
def main():
time.sleep(120)
signal.signal(signal.SIGTERM, handle_exit)
p = os.fork()
if p == 0:
main()
os._exit()
try:
os.waitpid(p, 0)
except (KeyboardInterrupt, SystemExit):
print('exit handled')
os.kill(p, 15)
os.waitpid(p, 0)
回答7:
The simplest solution I have found, taking inspiration by responses above is
class SignalHandler:
def __init__(self):
# register signal handlers
signal.signal(signal.SIGINT, self.exit_gracefully)
signal.signal(signal.SIGTERM, self.exit_gracefully)
self.logger = Logger(level=ERROR)
def exit_gracefully(self, signum, frame):
self.logger.info('captured signal %d' % signum)
traceback.print_stack(frame)
###### do your resources clean up here! ####
raise(SystemExit)
来源:https://stackoverflow.com/questions/18499497/how-to-process-sigterm-signal-gracefully