问题
I am in a situation where I need to find-out total time spent in office for some internal application.
I have sample data like this:
Id EmployeeId ScanDateTime Status
7 87008 2018-08-02 16:03:00.227 1
8 87008 2018-08-02 16:06:17.277 2
9 87008 2018-08-02 16:10:37.107 3
10 87008 2018-08-02 16:20:17.277 2
11 87008 2018-08-02 16:30:37.107 3
12 87008 2018-08-02 20:06:00.000 4
Here Status have different meanings:
1- Start 2- Pause 3- Resume 4- End
Means Employees start their work at ScanDateTime when status is 1. They can go for break(status 2) and come back and resume their work(Status 3) and with status 4 means they are ending their job. Note: There could be multiple breaks during work hours.
Expected Output:
EmployeeId StartTime EndTime BreakInMins
87008 2018-08-02 16:03:00.227 2018-08-02 20:06:00.000 14
I have tried to follow some example to calculate the expected result set but not helping.
I could not find any such example where this similar example available.
Any help would be appreciated.
回答1:
Please try this. Handles multiple breaks/employees and cases, when break is still in progress or session is not finished
select
[EmployeeId] = [s].[EmployeeId]
,[StartTime] = [s].[ScanDateTime]
,[EndTime] = [et].[ScanDateTime]
,[BreakInMins] = [b].[BreakInMins]
from
[Scans] as [s] -- here is your table
outer apply
(
select top 1 [ScanDateTime], [Id] from [Scans] where [Id] > [s].[Id] and [EmployeeId] = [s].[EmployeeId] and [Status] = 4 order by [ScanDateTime] asc
) as [et]
outer apply
(
select
[BreakInMins] = sum(isnull([r].[mins], datediff(mi, [sp].[ScanDateTime], getdate())))
from
[Scans] as [sp]
outer apply
(
select top 1 [mins] = datediff(mi, [sp].[ScanDateTime], [ScanDateTime]) from [Scans] where [Id] > [sp].[Id] and [EmployeeId] = [sp].[EmployeeId] and [Status] IN (3, 4) order by [ScanDateTime] asc
) as [r]
where
[sp].[id] > [s].[id] and [sp].[id] < isnull([et].[id], [id] + 1)
and [sp].[EmployeeId] = [s].[EmployeeId]
and [sp].[Status] = 2
) as [b]
where
[Status] = 1;
Here is test-friendly script: script
回答2:
i consider multiple breaks per day of employee you can check below i also provided fiddle link
select t1.*,t5.breakmins from
(
select EmployeeId,min(StartTime) as StartTime,max(EndTime) as EndTime from
(
select EmployeeId,(case when status=1 then ScanDateTime end) as StartTime,
(case when status=4 then ScanDateTime end) as EndTime,
case when status=3 then ScanDateTime end as ResumeWork,
case when status=2 then ScanDateTime end as pauseTime
from emp
) as t group by EmployeeId
) t1
inner join
(
select EmployeeId, convert(date,ResumeWork) as day ,
sum(case when status=2 then datediff(minute,ResumeWork,res) end ) as breakmins from
(
select EmployeeId,ResumeWork,status ,
lag(ResumeWork) over(PARTITION BY EmployeeId order by ResumeWork desc) as res from
(
select * from
(
select EmployeeId, case when status=3 then ScanDateTime end as ResumeWork,status from emp
) as t1 where ResumeWork is not null
union all
select * from
(
select EmployeeId,case when status=2 then ScanDateTime end as pauseTime,status from emp
) as t2 where pauseTime is not null
) as t3 group by EmployeeId,ResumeWork,status
) t4 group by EmployeeId, convert(date,ResumeWork)
)t5 on t1.EmployeeId=t5.EmployeeId
and convert(date,t1.StartTime)=t5.day
EmployeeId StartTime EndTime breakmins
87008 2018-08-02T16:03:00.227Z 2018-08-02T20:06:00Z 12
http://sqlfiddle.com/#!18/ae60f/6
回答3:
You can try this.
make a row_number in CTE by Status, because we need to know which Pause time correspond which Resume time. then self join in the CTE by EmployeeId
CREATE TABLE T(
Id INT,
EmployeeId INT,
ScanDateTime DATETIME,
Status INT
);
INSERT INTO T VALUES (7 ,87008 ,'2018-08-02 16:03:00.227',1);
INSERT INTO T VALUES (8 ,87008 ,'2018-08-02 16:06:17.277',2);
INSERT INTO T VALUES (9 ,87008 ,'2018-08-02 16:10:37.107',3);
INSERT INTO T VALUES (10,87008 ,'2018-08-02 16:20:17.277',2);
INSERT INTO T VALUES (11,87008 ,'2018-08-02 16:30:37.107',3);
INSERT INTO T VALUES (12,87008 ,'2018-08-02 20:06:00.000',4);
Query 1:
;with cte as(
SELECT *,
MIN(ScanDateTime) over(partition by EmployeeId order by EmployeeId) StartTime,
MAX(ScanDateTime) over(partition by EmployeeId order by EmployeeId) EndTime,
ROW_NUMBER() OVER(PARTITION BY Status order by id) rn
FROM t
)
select t1.EmployeeId,
t1.StartTime,
t1.EndTime,
SUM(datediff(minute,t1.ScanDateTime,t2.ScanDateTime)) BreakInMins
from
cte t1
inner join cte t2
on t1.rn =t2.rn and t1.Status = 2 and t2.Status = 3 and t1.EmployeeId = t2.EmployeeId
group by t1.EmployeeId,
t1.StartTime,
t1.EndTime
Results:
| EmployeeId | StartTime | EndTime | BreakInMins |
|------------|----------------------|--------------------------|-------------|
| 87008 | 2018-08-02T20:06:00Z | 2018-08-02T16:03:00.227Z | 14 |
EDIT
you can try this query if there are different day in your data. just group by the date.
CREATE TABLE T(
Id INT,
EmployeeId INT,
ScanDateTime DATETIME,
Status INT
);
INSERT INTO T VALUES (7 ,87008 ,'2018-08-02 16:03:00.227',1);
INSERT INTO T VALUES (8 ,87008 ,'2018-08-02 16:06:17.277',2);
INSERT INTO T VALUES (9 ,87008 ,'2018-08-02 16:10:37.107',3);
INSERT INTO T VALUES (10,87008 ,'2018-08-02 16:20:17.277',2);
INSERT INTO T VALUES (11,87008 ,'2018-08-02 16:30:37.107',3);
INSERT INTO T VALUES (12,87008 ,'2018-08-02 20:06:00.000',4);
INSERT INTO T VALUES (27 ,87008 ,'2018-08-03 16:03:00.227',1);
INSERT INTO T VALUES (28 ,87008 ,'2018-08-03 16:06:17.277',2);
INSERT INTO T VALUES (29 ,87008 ,'2018-08-03 16:11:37.107',3);
INSERT INTO T VALUES (210,87008 ,'2018-08-03 16:20:17.277',2);
INSERT INTO T VALUES (211,87008 ,'2018-08-03 16:30:37.107',3);
INSERT INTO T VALUES (212,87008 ,'2018-08-03 20:06:00.000',4);
Query 1:
;with cte as(
SELECT EmployeeId,
MAX(CASE WHEN Status = 1 then ScanDateTime end) StartTime,
MIN(CASE WHEN Status = 4 then ScanDateTime end) EndTime,
CAST(ScanDateTime as date) dt
FROM t
GROUP BY EmployeeId,CAST(ScanDateTime as date)
)
,cte2 as(
SELECT t2.*,
Row_number() over(partition by t2.EmployeeId,t2.Status order by Id) rn,
t1.StartTime,
t1.EndTime,
t1.dt
FROM cte t1
INNER JOIN T t2 ON t1.EmployeeId = t2.EmployeeId and Status in (2,3) and t1.dt = CAST(t2.ScanDateTime as date)
)
select t1.EmployeeId,
t1.StartTime,
t1.EndTime,
SUM(datediff(minute,t1.ScanDateTime,t2.ScanDateTime)) BreakInMins
from cte2 t1
inner join cte2 t2 on
t1.rn = t2.rn
and
t1.EmployeeId = t2.EmployeeId
and t1.Status = 2 and t2.Status =3
group by t1.EmployeeId,
t1.StartTime,
t1.EndTime
Results:
| EmployeeId | StartTime | EndTime | BreakInMins |
|------------|--------------------------|----------------------|-------------|
| 87008 | 2018-08-02T16:03:00.227Z | 2018-08-02T20:06:00Z | 14 |
| 87008 | 2018-08-03T16:03:00.227Z | 2018-08-03T20:06:00Z | 15 |
回答4:
Try below query: http://sqlfiddle.com/#!18/6fe11/3
select id,min(case when status=1 then stattime end) as starttime,
min(case when status=4 then stattime end) as endtime,
sum(case when status=2 then minute end) as breakinmin
from
(
select id,stattime,status,
DATEdiff(minute,stattime,lead(stattime,1,NULL)
over (partition by id ORDER BY stattime)) as minute
from ForgeRock)a
group by id
id starttime endtime breakinmin
87008 2018-08-02T16:03:00.227Z 2018-08-02T20:06:00Z 14
来源：https://stackoverflow.com/questions/51760743/find-time-spent-in-a-day-along-with-work-break-taken