Why does istream_iterator<string>(ifstream(“test.txt”)) cause an error?

喜你入骨 提交于 2020-01-03 17:08:23

问题


I have tried to write a code to read strings from file named "test.txt" and write the strings to standard output. The code below works well:

 int main()
 {
     using namespace std;
     ifstream file("test.txt");
     copy(istream_iterator<string>(file), 
          istream_iterator<string>(), 
          ostream_iterator<string>(cout, " ")); 
 }

However, with this modification, the code no longer compiles:

   int main()
   {
        using namespace std;
        copy(istream_iterator<string>(ifstream("test.txt")),  // <-- Error here
        istream_iterator<string>(), 
        ostream_iterator<string>(cout, " "));   
   }

Why doesn't this version compile?

The compiler I used is g++4.6.2, and the error as below:

ex11-16.cpp:16:65: error: no matching function for call to 'std::istream_iterator<std::basic_string<char> >::istream_iterator(std::ifstream)'
ex11-16.cpp:16:65: note: candidates are:
.../bits/stream_iterator.h:72:7: note: std::istream_iterator<_Tp, _CharT, _Traits, _Dist>::istream_iterator(const std::istream_iterator<_Tp, _CharT, _Traits, _Dist>&) [with _Tp = std::basic_string<char>, _CharT = char, _Traits = std::char_traits<char>, _Dist = int, std::istream_iterator<_Tp, _CharT, _Traits, _Dist> = std::istream_iterator<std::basic_string<char> >]
.../bits/stream_iterator.h:72:7: note:   no known conversion for argument 1 from 'std::ifstream {aka std::basic_ifstream<char>}' to 'const std::istream_iterator<std::basic_string<char> >&'
.../bits/stream_iterator.h:68:7: note: std::istream_iterator<_Tp, _CharT, _Traits, _Dist>::istream_iterator(std::istream_iterator<_Tp, _CharT, _Traits, _Dist>::istream_type&) [with _Tp = std::basic_string<char>, _CharT = char, _Traits = std::char_traits<char>, _Dist = int, std::istream_iterator<_Tp, _CharT, _Traits, _Dist>::istream_type = std::basic_istream<char>]
.../bits/stream_iterator.h:68:7: note:   no known conversion for argument 1 from 'std::ifstream {aka std::basic_ifstream<char>}' to 'std::istream_iterator<std::basic_string<char> >::istream_type& {aka std::basic_istream<char>&}'
.../bits/stream_iterator.h:64:26: note: std::istream_iterator<_Tp, _CharT, _Traits, _Dist>::istream_iterator() [with _Tp = std::basic_string<char>, _CharT = char, _Traits = std::char_traits<char>, _Dist = int]
.../bits/stream_iterator.h:64:26: note:   candidate expects 0 arguments, 1 provided

回答1:


There are (I believe) two errors here:

(1) You need to put quotations around test.txt:

istream_iterator<string>(ifstream("test.txt"), ... );

(2) istream_iterator's constructor takes in an istream& (that is, an lvalue reference to a stream). Consequently, the stream that you pass in has to be an lvalue. However, passing in ifstream("test.txt") passes in a temporary object of type ifstream, which is an rvalue rather than an lvalue. This is the same reason that you can't do this:

int function(int& x) {
    x++;
}
int main() {
    function(137); // Error - 137 is an rvalue, but lvalue is needed.
}

Hope this helps!



来源:https://stackoverflow.com/questions/17246720/why-does-istream-iteratorstringifstreamtest-txt-cause-an-error

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