问题
How to pass a custom php.ini to phpunit?
The source uses
get_cfg_var
instead of
ini_get
so unfortunately it doesn't use values set by ini_set, -d option etc.
Only way to pass the value now is to use an additional php.ini. How do I pass that into phpunit?
Gory details:
I tried passing in with -d
phpunit --filter testgetdesc -d SIEF_VALIDATOR_DOC_ROOT="htdocs"
--configuration tests/phpunit.xml tests/configHelperTest.php
public function testgetdesc() {
echo get_cfg_var("SIEF_VALIDATOR_DOC_ROOT")."---test---";
}
It simply echoes "---test---"
The reason is this uses ini_set as well:
https://github.com/sebastianbergmann/phpunit/blob/master/PHPUnit/TextUI/Command.php
case 'd': {
$ini = explode('=', $option[1]);
if (isset($ini[0])) {
if (isset($ini[1])) {
ini_set($ini[0], $ini[1]);
} else {
ini_set($ini[0], TRUE);
}
}
}
Also in the phpunit.xml, I have
<php>
<ini name="SIEF_VALIDATOR_DOC_ROOT" value="bar"/>
</php>
which doesn't work [and I don't expect it to].
回答1:
-d
should work because get_cfg_var
reads those:
$ php -d display.errors2=1 -r "echo get_cfg_var('display.errors2');"
1
To pass a custom ini setting (or alternatively the ini file with -c <file>
to phpunit), invoke it configured:
$ php -d setting=value `which phpunit` <your params>
See as well: php --help
, http://www.phpunit.de/manual/3.6/en/appendixes.configuration.html
回答2:
The Github issue recommends using the -c
flag.
php -c custom-php.ini `which phpunit` ...
来源:https://stackoverflow.com/questions/7723959/passing-custom-php-ini-to-phpunit