问题
Let`s have a example hotels table:
CREATE TABLE `hotels` (
`HotelNo` varchar(4) character set latin1 NOT NULL default '0000',
`Hotel` varchar(80) character set latin1 NOT NULL default '',
`City` varchar(100) character set latin1 default NULL,
`CityFR` varchar(100) character set latin1 default NULL,
`Region` varchar(50) character set latin1 default NULL,
`RegionFR` varchar(100) character set latin1 default NULL,
`Country` varchar(50) character set latin1 default NULL,
`CountryFR` varchar(50) character set latin1 default NULL,
`HotelText` text character set latin1,
`HotelTextFR` text character set latin1,
`tagsforsearch` text character set latin1,
`tagsforsearchFR` text character set latin1,
PRIMARY KEY (`HotelNo`),
FULLTEXT KEY `fulltextHotelSearch` (`HotelNo`,`Hotel`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`,`HotelText`,`HotelTextFR`,`tagsforsearch`,`tagsforsearchFR`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_german1_ci;
In this table for example we have only one hotel with Region name = "Graubünden" (please note umlaut ü character)
And now I want to achieve same search match for phrases: 'graubunden' and 'graubünden'
This is simple with use of MySql built in collations in regular searches as follows:
SELECT *
FROM `hotels`
WHERE `Region` LIKE CONVERT(_utf8 '%graubunden%' USING latin1)
COLLATE latin1_german1_ci
This works fine for 'graubunden' and 'graubünden' and as a result I receive proper result, but problem is when we make MySQL full text search
Whats wrong with this SQL statement?:
SELECT
*
FROM
hotels
WHERE
MATCH (`HotelNo`,`Hotel`,`Address`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`, `HotelText`, `HotelTextFR`, `tagsforsearch`, `tagsforsearchFR`)
AGAINST( CONVERT('+graubunden' USING latin1) COLLATE latin1_german1_ci IN BOOLEAN MODE)
ORDER BY Country ASC, Region ASC, City ASC
This doesn`t return any result. Any ideas where the dog is buried ?
回答1:
When you define individual CHARACTER SETS
for your columns, you override the collation you set default on table level.
Each of your columns has default latin1
collation (which is latin1_swedish_ci
). You can see it by running SHOW CREATE TABLE
.
In FULLTEXT
queries, indexed columns have COERCIBILITY
of 0
, that is all fulltext queries are converted to the collation used in the index, not vice versa.
You need to remove CHARACTER SET
definitions from your columns or explicitly set all columns to latin1_german_ci
:
CREATE TABLE `hotels` (
`HotelNo` varchar(4) NOT NULL default '0000',
`Hotel` varchar(80) NOT NULL default '',
`City` varchar(100) default NULL,
`CityFR` varchar(100) default NULL,
`Region` varchar(50) default NULL,
`RegionFR` varchar(100) default NULL,
`Country` varchar(50) default NULL,
`CountryFR` varchar(50) default NULL,
`HotelText` text,
`HotelTextFR` text,
`tagsforsearch` text,
`tagsforsearchFR` text,
PRIMARY KEY (`HotelNo`),
FULLTEXT KEY `fulltextHotelSearch` (`HotelNo`,`Hotel`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`,`HotelText`,`HotelTextFR`,`tagsforsearch`,`tagsforsearchFR`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_german1_ci;
INSERT
INTO hotels (hotelText, HotelTextFR, tagsforsearch, tagsforsearchFR)
VALUES ('text', 'text', 'graubünden', 'tags');
SELECT *
FROM hotels
WHERE MATCH (`HotelNo`,`Hotel`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`, `HotelText`, `HotelTextFR`, `tagsforsearch`, `tagsforsearchFR`)
AGAINST (CONVERT('+graubunden' USING latin1) COLLATE latin1_german1_ci IN BOOLEAN MODE)
ORDER BY
Country ASC, Region ASC, City ASC;
来源:https://stackoverflow.com/questions/2722044/mysql-german-accents-not-sensitive-search-in-full-text-searches