问题
I have a hierarchy of directories containing many text files. I would like to search for a particular text string every time it comes up in one of the files, and replace it with another string. For example, I may want to replace every occurrence of the string "Coke" with "Pepsi". Does anyone know how to do this? I am wondering if there is some sort of Bash command that can do this without having to load all these files in an editor, or come up with a more complex script to do it.
I found this page explaining a trick using sed, but it doesn't seem to work in files in subdirectories.
回答1:
Use sed in combination with find. For instance:
find . -name "*.txt" | xargs sed -i s/Coke/Pepsi/g
or
find . -name "*.txt" -exec sed -i s/Coke/Pepsi/g {} \;
(See the man page on find for more information)
回答2:
Combine sed with find like this:
find . -name "file.*" -exec sed -i 's/Coke/Pepsi/g' {} \;
回答3:
IMO, the tool with the easiest usage for this task is rpl:
rpl -R Coke Pepsi .
(-R is for recursive replacement in all subdirectories)
回答4:
find . -type f -exec sed -i 's/old-word/new-word/g' {} \;
回答5:
I usually do it in perl. However watch out - it uses regexps which are much more powerful then normal string substitution:
% perl -pi -e 's/Coke/Pepsi/g;' $filename
EDIT I forgot about subdirectories
% find ./ -exec perl -pi -e 's/Coke/Pepsi/g;' {} \;
回答6:
you want a combination of find and sed
回答7:
You may also:
Search & replace with find & ed
http://codesnippets.joyent.com/posts/show/2299
(which also features a test mode via -t flag)
来源：https://stackoverflow.com/questions/2860170/bash-any-command-to-replace-strings-in-text-files