问题
Is there a way to get this information from the /proc
directory? I want to be able to get how long each process has been running on seconds.
EDIT: I needed to do this from C++. Sorry for the confusion.
回答1:
Okay guys, so after reading the top
command's source code, I figured out a non-hacky way of getting the start time of a process. The formula that they use is:
Process_Time = (current_time - boot_time) - (process_start_time)/HZ.
(You have to divide by HZ because process_start_time is in jiffies)
Obtaining these values:
current_time
- You can get this from the C commandgettimeofday()
.boot_time
- This value is located in/proc/uptime
. This file contains two numbers: the uptime of the system (seconds), and the amount of time spent in idle process (seconds). Take the first.process_start_time
- This value is located in/proc/[PID]/stat
. The time difference (in jiffies) between system boot and when the process started. (The 22nd value in the file if you split on whitespace).
The code (Sorry, I sometimes mix c and c++):
int fd;
char buff[128];
char *p;
unsigned long uptime;
struct timeval tv;
static time_t boottime;
if ((fd = open("/proc/uptime", 0)) != -1)
{
if (read(fd, buff, sizeof(buff)) > 0)
{
uptime = strtoul(buff, &p, 10);
gettimeofday(&tv, 0);
boottime = tv.tv_sec - uptime;
}
close(fd);
}
ifstream procFile;
procFile.open("/proc/[INSERT PID HERE]/stat");
char str[255];
procFile.getline(str, 255); // delim defaults to '\n'
vector<string> tmp;
istringstream iss(str);
copy(istream_iterator<string>(iss),
istream_iterator<string>(),
back_inserter<vector<string> >(tmp));
process_time = (now - boottime) - (atof(tmp.at(21).c_str()))/HZ;
Happy Coding!
回答2:
You can do stat /proc/{processid}
to see the creation time at the shell.
EDIT: fstat on that folder should give you what you want (the creation time).
回答3:
Let's break down what you're trying to do:
- Get the time the file was modified.
- Convert the time into Unix time.
- Subtract the two times.
So, in order to get the current time, we can run:
#include <cstdio>
#include <cstdlib>
char *command;
int process_number = 1; // init process.
SYSTEM ("mkfifo time_pipe");
sprintf (command, "stat /proc/%d -printf="%%X" > time_pipe", process_number); // get the command to run.
// since this directory is created once it starts, we know it is the start time (about)
// note the %%, which means to print a literal %
SYSTEM (command); // run the command.
Now, the next step is parsing it to Unix time -- but we don't have to! The %X specifier actually converts it to Unix Time. So next step would be to (a) get the current time (b) subtract the times:
timeval cur_time;
double current_time, time_passed;
char read_time[11]; // 32 bit overflows = only 11 digits.
FILE *ourpipe;
gettimeofday(&cur_time, NULL);
current_time = cur_time.tv_sec + (cur_time.tv_usec * 1000000.0);
// usec stands for mu second, i.e., a millionth of a second. I wasn't there when they named this stuff.
ourpipe = fopen ("time_pipe", "rb");
fread(read_time, sizeof (char), 10, ourpipe);
time_passed = current_time - atoi (read_time);
fclose (ourpipe);
So yeah, that's pretty much it. The pipe is needed to get the input from one to the other.
回答4:
The time command will give you that info:
> man 1 time
Command-line arguments will make it return
%S Total number of CPU-seconds that the process spent in kernel mode.
%U Total number of CPU-seconds that the process spent in user mode.
%P Percentage of the CPU that this job got
You can call system( char *command )
to execute the command from your prog.
回答5:
/proc/{processid} # Good idea!
But why not just read /proc/{processid}/stat, and simply get whatever statistics you want?
from "man proc":
...
stat kernel/system statistics
cpu 3357 0 4313 1362393
The number of jiffies (1/100ths of a second)
that the system spent in user mode, user
mode with low priority (nice), system mode,
and the idle task, respectively. The last
value should be 100 times the second entry
in the uptime pseudo-file.
disk 0 0 0 0
The four disk entries are not implemented at
this time. I'm not even sure what this
should be, since kernel statistics on other
machines usually track both transfer rate
and I/Os per second and this only allows for
one field per drive.
...
回答6:
Old topic this, but since I was working on the same issues, I thought I might post my response. Perhaps it would be useful for someone else. Note, this code should not be used in a serious production environment, but as a quick and dirty way to get what the OP is looking for, I think this would be sufficient. Note that this code is the same code as OP posted in response to his own question, but it is modified to be able to be directly compiled when you copy it from stackexchange, his code was not directly able to compile.
This code compile, and I've added a few extra functions.
Instructions: Start any program, then do a 'ps aux | programname' to get its pid. It's the second column from the left. Now input that number to pid in the main function and compile the program. Now, when running the program, the output will be something like:
Lapsed: days: 0 , hours: 0 , min: 5 , seconds: 58
//Original code credit by kmdent.
//http://stackoverflow.com/questions/6514378/how-do-you-get-how-long-a-process-has-been-running
#include <iostream>
#include <iterator>
#include <sstream>
#include <fstream>
#include <vector>
#include <cstring>
#include <cerrno>
#include <ctime>
#include <cstdio>
#include <fcntl.h>
#include <sys/time.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <stdlib.h>
#include <string>
#include "/usr/include/x86_64-linux-gnu/sys/param.h"
using namespace std;
template <class T>
inline std::string to_string (const T& t)
{
std::stringstream ss;
ss << t;
return ss.str();
}
//Return the number of seconds a process has been running.
long lapsed(string pid) {
int fd;
char buff[128];
char *p;
unsigned long uptime;
struct timeval tv;
static time_t boottime;
if ((fd = open("/proc/uptime", 0)) != -1) {
if (read(fd, buff, sizeof(buff)) > 0) {
uptime = strtoul(buff, &p, 10);
gettimeofday(&tv, 0);
boottime = tv.tv_sec - uptime;
}
close(fd);
}
ifstream procFile;
string f = "/proc/"+pid+"/stat";
procFile.open(f.c_str());
char str[255];
procFile.getline(str, 255); // delim defaults to '\n'
vector<string> tmp;
istringstream iss(str);
copy(istream_iterator<string>(iss),
istream_iterator<string>(),
back_inserter<vector<string> >(tmp));
std::time_t now = std::time(0);
std::time_t lapsed = ((now - boottime) - (atof(tmp.at(21).c_str()))/HZ);
return lapsed;
}
string human_readable_lapsed(long input_seconds) {
//Credit: http://www.cplusplus.com/forum/beginner/14357/
long days = input_seconds / 60 / 60 / 24;
int hours = (input_seconds / 60 / 60) % 24;
int minutes = (input_seconds / 60) % 60;
int seconds = input_seconds % 60;
return "days: " + to_string(days) + " , hours: " + to_string(hours) + " , min: " + to_string(minutes) + " , seconds: " + to_string(seconds);
}
int main(int argc, char* argv[])
{
//Pid to get total running time for.
string pid = "13875";
std::cout << "Lapsed: " << human_readable_lapsed(lapsed(pid)) << std::endl;
return 0;
}
来源:https://stackoverflow.com/questions/6514378/how-do-you-get-how-long-a-process-has-been-running