问题
I'd like to write a method which does some work and finally returns another method with the same signature as the original method. The idea is to handle a stream of bytes depending on the previous byte value sequentially without going into a recursion. By calling it like this:
MyDelegate executeMethod = handleFirstByte //What form should be MyDelegate?
foreach (Byte myByte in Bytes)
{
executeMethod = executeMethod(myByte); //does stuff on byte and returns the method to handle the following byte
}
To handover the method I want to assign them to a Func delegate. But I ran into the problem that this results in a recursive declaration without termination...
Func<byte, Func<byte, <Func<byte, etc... >>>
I'm somehow lost here. How could I get around that?
回答1:
You can simply declare a delegate type when the predefined Func<...>
delegates aren't sufficient:
public delegate RecursiveFunc RecursiveFunc(byte input);
And in case you need it, you can use generics too:
public delegate RecursiveFunc<T> RecursiveFunc<T>(T input);
来源:https://stackoverflow.com/questions/27989296/how-do-i-declare-a-func-delegate-which-returns-a-func-delegate-of-the-same-type