How to do an explicit fall-through in C

问题

The newer versions of gcc offer the Wimplicit-fallthrough, which is great to have for most switch statements. However, I have one switch statement where I want to allow fall throughs from all case-statements.

Is there a way to do an explicit fall through? I'd prefer to avoid having to compile with Wno-implicit-fallthrough for this file.

EDIT: I'm looking for a way to make the fall through explicit (if it's possible), not to turn off the warning via a compiler switch or pragma.

回答1:

Use __attribute__ ((fallthrough))

switch (condition) {
    case 1: __attribute__ ((fallthrough));
    case 2: __attribute__ ((fallthrough));
    case 3:
        printf("1..3\n");
        break;
}

回答2:

You should be able to use GCC diagnostic pragmas to disable that particular warning for your source file or some portion of a source file. Try putting this at the top of your file:

#pragma GCC diagnostic ignored "-Wimplicit-fallthrough"

回答3:

GCC fallghrough magic comments

You should not use this, it is insane, but good to know about:

int main(int argc, char **argv) {
    (void)argv;
    switch (argc) {
        case 0:
            argc = 1;
            // fall through
        case 1:
            argc = 2;
    };
}

prevents the warning on GCC 7.4.0 with:

gcc -Wall -Wextra main.c

man gcc describes how different comments may or not be recognized depending on the value of:

-Wimplicit-fallthrough=n

C++17 [[fallthrough]] attribute

C++17 got a standardized syntax for this: GCC 7, -Wimplicit-fallthrough warnings, and portable way to clear them?

来源：https://stackoverflow.com/questions/44511436/how-to-do-an-explicit-fall-through-in-c

标签

gcc

c99

gcc-warning