问题
I want to serialize ObjectId of my Product
class to JSON. I got the following JSON:
[{"name":"Play for Java: Covers Play 2","type":"Book","company":"Manning Publications","price":30.0,"imagePath":"public/images/play-for-java.png","rating":4.5,"category":"Computer","author":"Nicolas Leroux","publicationDate":1396224000000,"numPage":320,"_id":539da7a6370882f10d5c2777}]
You can notice that the "_id"
didn't be properly serialized, it should be "539da7a6370882f10d5c2777"
(with double quotes) and not just 539da7a6370882f10d5c2777
.
Therefore, I have tried to implement my own ObjectIdSerializer
as following:
import java.io.IOException;
import org.bson.types.ObjectId;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.SerializerProvider;
public class ObjectIdSerializer extends JsonSerializer<ObjectId> {
@Override
public void serialize(ObjectId value, JsonGenerator jsonGen,SerializerProvider provider) throws IOException,
JsonProcessingException {
jsonGen.writeString(value.toString());
}
}
It gave me the different error: java.lang.String cannot be cast to org.bson.types.ObjectId (through reference chain: models.Book["_id"])
Here are my Product
class and Book
class:
Product.java
@JsonTypeInfo(use= JsonTypeInfo.Id.CLASS,property="_class")
public class Product {
@ObjectId @Id
@JsonSerialize(using = ObjectIdSerializer.class)
protected String id;
@JsonProperty("name")
protected String name;
@JsonProperty("type")
protected String type;
@JsonProperty("description")
protected String description;
@JsonProperty("company")
protected String company;
@JsonProperty("price")
protected float price;
@JsonProperty("imagePath")
protected String imagePath;
@JsonProperty("imageName")
protected String imageName;
@JsonProperty("rating")
protected float rating;
public Product() {
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
// Getters and setters
...
Book.java
public class Book extends Product{
@JsonProperty("category")
private String category;
@JsonProperty("author")
private String author;
@JsonProperty("publicationDate")
private Date publicationDate;
@JsonProperty("numPage")
private int numPage;
public Book() {
}
// Getters and setters
...
Can you help me figure it out how can I properly serialize the ObjectId
to JSON?
回答1:
It looks like Jackson has been customized to serialize the string id field in a special way. That is probably a part of the integration with org.bson
library.
The problem is that your deserializer is parametrized by the ObjectId
type instead of String
or plain Object
. Try to change it as follows and also remove the @ObjectId
annotation from the field declaration. Here is an example:
public class ObjectIdSerializer extends JsonSerializer<Object> {
@Override
public void serialize(Object value, JsonGenerator jsonGen,SerializerProvider provider) throws IOException {
jsonGen.writeString(value.toString());
}
}
You may also consider adopting the Jackson-Jongo provider class to fix the object id serialization for all the classes.
来源:https://stackoverflow.com/questions/24230526/how-to-serialize-objectid-to-json