问题
i am trying to open a file with ifstream and i want to use a string as the path (my program makes a string path). it will compile but it stays blank.
string path = NameOfTheFile; // it would be something close to "c:\file\textfile.txt"
string line;
ifstream myfile (path); // will compile but wont do anything.
// ifstream myfile ("c:\\file\\textfile.txt"); // This works but i can't change it
if (myfile.is_open())
{
while (! myfile.eof() )
{
getline (myfile,line);
cout << line << endl;
}
}
I am using windows 7, My compiler is VC++ 2010.
回答1:
string path = compute_file_path();
ifstream myfile (path.c_str());
if (!myfile) {
// open failed, handle that
}
else for (string line; getline(myfile, line);) {
use(line);
}
回答2:
Have you tried ifstream myfile(path.c_str());
?
See a previous post about the problems with while (!whatever.eof())
.
回答3:
I'm unsure as to how this actually compiles, but I assume you are looking for:
#include <fstream>
#include <string>
//...
//...
std::string filename("somefile.txt");
std::ifstream somefile(filename.c_str());
if (somefile.is_open())
{
// do something
}
回答4:
//Check out piece of code working for me
//---------------------------------------
char lBuffer[100];
//---
std::string myfile = "/var/log/mylog.log";
std::ifstream log_file (myfile.str());
//---
log_file.getline(lBuffer,80);
//---
来源:https://stackoverflow.com/questions/4881210/how-to-convert-a-string-to-a-ifstream